제출 #405675

#제출 시각아이디문제언어결과실행 시간메모리
405675AmineWeslatiCat in a tree (BOI17_catinatree)C++14
51 / 100
1081 ms15668 KiB
//Never stop trying #include "bits/stdc++.h" using namespace std; #define boost ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0) typedef long long ll; #define int ll typedef string str; typedef long double ld; typedef pair<int, int> pi; #define fi first #define se second typedef vector<int> vi; typedef vector<pi> vpi; #define pb push_back #define eb emplace_back #define sz(x) (int)x.size() #define all(x) begin(x), end(x) #define rall(x) rbegin(x), rend(x) #define endl "\n" #define FOR(i,a,b) for (int i = (a); i < (b); ++i) #define ROF(i,a,b) for (int i = (b)-1; i >= (a); --i) const int MOD = 1e9 + 7; //998244353 const ll INF = 1e18; const int MX = 2e5 + 10; const int nx[4] = {0, 0, 1, -1}, ny[4] = {1, -1, 0, 0}; //right left down up template<class T> using V = vector<T>; template<class T> bool ckmin(T& a, const T& b) { return a > b ? a = b, 1 : 0; } template<class T> bool ckmax(T& a, const T& b) { return a < b ? a = b, 1 : 0; } ll cdiv(ll a, ll b) { return a / b + ((a ^ b) > 0 && a % b); } // divide a by b rounded up //constexpr int log2(int x) { return 31 - __builtin_clz(x); } // floor(log2(x)) mt19937 rng(chrono::system_clock::now().time_since_epoch().count()); //mt19937_64 rng(chrono::system_clock::now().time_since_epoch().count()); ll random(ll a, ll b){ return a + rng() % (b - a + 1); } #ifndef LOCAL #define cerr if(false) cerr #endif #define dbg(x) cerr << #x << " : " << x << endl; #define dbgs(x,y) cerr << #x << " : " << x << " / " << #y << " : " << y << endl; #define dbgv(v) cerr << #v << " : " << "[ "; for(auto it : v) cerr << it << ' '; cerr << ']' << endl; #define here() cerr << "here" << endl; void IO() { #ifdef LOCAL freopen("input.txt", "r", stdin); freopen("output.txt", "w", stdout); #endif } /////////////////////////ONLY CLEAN CODES ALLOWED///////////////////////// int N,D; vi adj[MX]; vi dist(MX); void dfs(int u){ if(dist[u]==-1) dist[u]=0; for(int v: adj[u]) if(dist[v]==-1){ dist[v]=dist[u]+1; dfs(v); } } int32_t main() { boost; IO(); cin>>N>>D; FOR(v,1,N){ int u; cin>>u; adj[u].pb(v); adj[v].pb(u); } FOR(i,0,N) dist[i]=-1; dfs(0); int cur=0; FOR(i,0,N) if(dist[i]>dist[cur]) cur=i; vi v(N,INF); int ans=0; while(1){ ans++; FOR(i,0,N) dist[i]=-1; dfs(cur); FOR(i,0,N) ckmin(v[i],dist[i]); int nxt=-1; FOR(i,0,N) if(v[i]>=D){ if(nxt==-1) nxt=i; else if(dist[i]>dist[nxt]) nxt=i; } if(nxt==-1) break; cur=nxt; } cout << ans << endl; return 0; } //Change your approach
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