이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define DIM 100010
#define INF 10000000
using namespace std;
int dp[DIM][2][2],v[DIM];
vector <int> L[DIM];
int n,i,x,y;
void dfs (int nod, int tata){
int ok = 0;
for (auto vecin : L[nod])
if (vecin != tata){
ok = 1;
dfs (vecin,nod);
}
if (!ok){
dp[nod][v[nod]][0] = 0;
dp[nod][1-v[nod]][1] = 1;
} else {
/// caz 1: nu dau switch in nod
int sum = 0, cnt = 0;
for (auto vecin : L[nod]){
if (vecin == tata)
continue;
if (dp[vecin][0][0] < dp[vecin][0][1])
sum += dp[vecin][0][0];
else {
sum += dp[vecin][0][1];
cnt++;
}
}
if (cnt % 2 == 0)
dp[nod][v[nod]][0] = sum;
else dp[nod][1-v[nod]][0] = sum;
/// incerc sa schimb paritatea lui cnt
int mini = INF;
for (auto vecin : L[nod]){
if (vecin == tata)
continue;
if (dp[vecin][0][0] < dp[vecin][0][1])
mini = min (mini,sum - dp[vecin][0][0] + dp[vecin][0][1]);
else mini = min (mini,sum - dp[vecin][0][1] + dp[vecin][0][0]);
}
if (cnt % 2 == 0)
dp[nod][1-v[nod]][0] = mini;
else dp[nod][v[nod]][0] = mini;
/// caz 2: dau switch in nod
cnt = 1, sum = 0;
for (auto vecin : L[nod]){
if (vecin == tata)
continue;
if (dp[vecin][1][0] < dp[vecin][1][1])
sum += dp[vecin][1][0];
else {
sum += dp[vecin][1][1];
cnt++;
}
}
if (cnt % 2 == 0)
dp[nod][v[nod]][1] = 1 + sum;
else dp[nod][1-v[nod]][1] = 1 + sum;
/// schimb starea din nod
mini = INF;
for (auto vecin : L[nod]){
if (vecin == tata)
continue;
if (dp[vecin][1][0] < dp[vecin][1][1])
mini = min (mini,sum - dp[vecin][1][0] + dp[vecin][1][1]);
else mini = min (mini, sum - dp[vecin][1][1] + dp[vecin][1][0]);
}
if (cnt % 2 == 0)
dp[nod][1-v[nod]][1] = 1 + mini;
else dp[nod][v[nod]][1] = 1 + mini;
}
}
int main (){
//ifstream cin ("date.in");
//ofstream cout ("date.out");
cin>>n;
for (i=1;i<n;i++){
cin>>x>>y;
L[x].push_back(y);
L[y].push_back(x);
}
for (i=1;i<=n;i++){
cin>>v[i];
dp[i][0][0] = dp[i][0][1] = dp[i][1][0] = dp[i][1][1] = INF;
}
dfs (1,0);
int sol = min(dp[1][0][0],dp[1][0][1]);
if (sol == INF)
cout<<"impossible";
else cout<<sol;
return 0;
}
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