Submission #404200

#TimeUsernameProblemLanguageResultExecution timeMemory
404200Kenzo_1114Friend (IOI14_friend)C++17
46 / 100
32 ms5324 KiB
#include<bits/stdc++.h> #include"friend.h" using namespace std; const int MAXN = 100010; int n, c[MAXN], h[MAXN], p[MAXN]; /* 0 : IAmYourFriend 1 : MyFriendsAreYourFriends 2 : WeAreYourFriends */ int Bkt = 0; bool mark[20], adj[20][20]; void bkt(int id) { if(id == n) { bool ok = true; for(int i = 0; i < n; i++) for(int j = i + 1; j < n; j++) if(mark[i] && mark[j] && adj[i][j]) ok = false; if(!ok) return; int sum = 0; for(int i = 0; i < n; i++) if(mark[i]) sum += c[i]; Bkt = max(Bkt, sum); return; } mark[id] = true; bkt(id + 1); mark[id] = false; bkt(id + 1); } int task1() { for(int i = 1; i < n; i++) { int a = h[i]; int b = i; if(p[i] == 0 || p[i] == 2) adj[a][b] = adj[b][a] = true; if(p[i] > 0) for(int j = 0; j < n; j++) if(a != j && adj[a][j]) adj[b][j] = adj[j][b] = true; } bkt(0); return Bkt; } int task2() { int ans = 0; for(int i = 0; i < n; i++) { if(i && p[i] != 1) return 0; ans += c[i]; } return ans; } int task3() { int ans = 0; for(int i = 0; i < n; i++) { if(i && p[i] != 2) return 0; ans = max(ans, c[i]); } return ans; } int dp[2][MAXN]; vector<int> graph[MAXN]; int dfs4(int v, int p) { dp[1][v] = c[v]; for(int i = 0; i < (int) graph[v].size(); i++) { int u = graph[v][i]; if(u == p) continue; dp[0][v] += dfs4(u, v); dp[1][v] += dp[0][u]; } return max(dp[0][v], dp[1][v]); } int task4() { for(int i = 1; i < n; i++) if(p[i] != 0) return 0; for(int i = 1; i < n; i++) { int a = h[i]; int b = i; graph[a].push_back(b); graph[b].push_back(a); } return dfs4(0, 0); } int color[MAXN]; int task5() { for(int i = 1; i < n; i++) { int a = h[i]; int b = i; if(p[i] == 0) color[b] = !color[a]; else color[b] = color[a]; } int ans[2] = {0, 0}; for(int i = 0; i < n; i++) ans[color[i]] += c[i]; return max(ans[0], ans[1]); } int findSample(int N, int Confidence[], int Host[], int Protocol[]) { n = N; for(int i = 0; i < N; i++) c[i] = Confidence[i]; for(int i = 0; i < N; i++) h[i] = Host[i]; for(int i = 0; i < N; i++) p[i] = Protocol[i]; if(n <= 10) return task1(); int ans = task2(); if(ans) return ans; ans = task3(); if(ans) return ans; ans = task4(); if(ans) return ans; return task5(); }
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