이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <bits/stdc++.h>
#define fi first
#define se second
#define pb push_back
#define sz(a) (int)a.size()
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define ff(i,a,b) for(int i=a;i<=b;i++)
#define fb(i,b,a) for(int i=b;i>=a;i--)
using namespace std;
using namespace __gnu_pbds;
typedef long long ll;
typedef pair<int,int> pii;
const int maxn = 100005;
const ll inf = 1e18 + 5;
template<typename T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
// os.order_of_key(k) the number of elements in the os less than k
// *os.find_by_order(k) print the k-th smallest number in os(0-based)
int n, K;
int niz[maxn];
ll pref[maxn];
ll dp[maxn][2];
int put[maxn][205];
void divi(int lvl, int tl, int tr, int l, int r) {
if(l > r)return;
int mid = (l + r) / 2;
dp[mid][lvl & 1] = -inf;
int opt = 0;
ff(i,tl,min(mid,tr)) {
ll kol = (pref[mid] - pref[i - 1]) * (pref[n] - pref[mid]);
if(dp[i - 1][!(lvl & 1)] + kol >= dp[mid][lvl & 1]) {
dp[mid][lvl & 1] = dp[i - 1][!(lvl & 1)] + kol;
opt = i;
}
}
put[mid][lvl] = opt - 1;
divi(lvl, tl, opt, l, mid - 1);
divi(lvl, opt, tr, mid + 1, r);
}
int main()
{
ios::sync_with_stdio(false);
cout.tie(nullptr);
cin.tie(nullptr);
cin >> n >> K;
ff(i,1,n)cin >> niz[i];
ff(i,1,n)pref[i] = pref[i - 1] + niz[i];
K += 1;
ff(i,1,n)dp[i][1] = pref[i] * (pref[n] - pref[i]);
ff(j,2,K)divi(j,1,n,1,n);
vector<int> res;
cout << dp[n][K & 1] << '\n';
int cur = n;
fb(i,K,2)cout << put[cur][i] << " ", cur = put[cur][i];
return 0;
}
/**
2 1
0 123
9 4
51 57 35 8 14 30 2 55 13
7 3
4 1 3 4 0 2 3
4 1 3 |
// probati bojenje sahovski ili slicno
**/
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