제출 #402705

#제출 시각아이디문제언어결과실행 시간메모리
402705luisgalan콤보 (IOI18_combo)C++14
5 / 100
1661 ms988 KiB
#include<bits/stdc++.h> #include "combo.h" using namespace std; #define debug(x) cerr << #x << " = " << (x) << endl vector<vector<int>> possible; char chars[4] = {'A', 'B', 'X', 'Y'}; map<char, int> charsinv; string guess_sequence(int n) { charsinv.insert({'A', 0}); charsinv.insert({'B', 1}); charsinv.insert({'X', 2}); charsinv.insert({'Y', 3}); vector<int> res; int init; possible = vector<vector<int>>(n); fill(possible.begin(), possible.end(), vector<int> { 1, 1, 1, 1 }); if (press("AB")) { init = press("A") ? 0 : 1; } else { init = press("X") ? 2 : 3; } res.push_back(init); vector<char> others; for (int i = 0; i < 4; i++) { if (i == init) continue; others.push_back(i); } for (int i = 0; i < n; i++) { possible[i][init] = 0; } while (true) { bool done = true; for (int i = 0; i < n-1; i++) { if (accumulate(possible[i].begin(), possible[i].end(), 0) > 1) { done = false; break; } } if (done) break; vector<string> queries = { string(1, chars[init]) }; int i = 0; int size = 0; // while (2 * queries.size() * (queries[0].size() + 1) <= 4 * n && i + 1 < n) { while (i + 1 < n) { // debug(queries[0].size()); vector<string> queries_next; int choice_1 = init; while (!possible[i][choice_1]) choice_1 = rand() % 4; int choice_2 = init; while (!possible[i][choice_2]) choice_2 = rand() % 4; for (string &query : queries) { int num_possible = accumulate(possible[i].begin(), possible[i].end(), 0); if (num_possible == 3) { queries_next.push_back(query + chars[choice_1]); queries_next.push_back(query + chars[choice_2]); } else { queries_next.push_back(query + chars[choice_1]); } } int size = 0; for (auto &q : queries_next) size += q.size(); if (size > 4 * n) { break; } queries = queries_next; i++; } string query = ""; vector<vector<int>> possible_q(n); fill(possible_q.begin(), possible_q.end(), vector<int> { 0, 0, 0, 0 }); for (string q : queries) { query += q; for (int i = 0; i < q.size(); i++) { if (q[i] == chars[init]) continue; possible_q[i-1][charsinv[q[i]]] = 1; } } // for (int i = 0; i < n; i++) { // for (int j = 0; j < 4; j++) { // cerr << possible_q[i][j]; // } // cerr << " "; // }; // cerr << endl; // debug(query.size()); // debug(query); int coins = press(query); // debug(coins); for (int i = 0; i < coins - 2; i++) { for (int j = 0; j < 4; j++) { possible[i][j] = possible[i][j] && possible_q[i][j]; } } for (int j = 0; j < 4; j++) { possible[coins-1][j] = possible[coins-1][j] && !possible_q[coins-1][j]; } // cerr << "possible: "; // for (int i = 0; i < n; i++) { // for (int j = 0; j < 4; j++) { // cerr << possible[i][j]; // } // cerr << " "; // }; // cerr << endl; } string ans = ""; ans += chars[init]; for (int i = 0; i < n-1; i++) { for (int j = 0; j < 4; j++) { if (possible[i][j]) ans += chars[j]; } } return ans; } // we can cross out possible characters in parallel // check first two chars for i and i + 1 // i has 111 and i+1 has 111 // try 110, 110 // if +2: i <- 110, b <- 110 // if +1: i <- 110, b <- 001 // if +0: i <- 001, b <- 111 // i has 111 and i+1 has 111 // try 100, 100 // if +2: i <- 100, b <- 100 // if +1: i <- 100, b <- 011 // if +0: i <- 011, b <- 111 // i has 110 and i+1 has 110 // try 100, 100 // if +2: i <- 100, b <- 100 // if +1: i <- 100, b <- 010 // if +0: i <- 010 // i has 110 and i+1 has 110 and i+2 has 111 // try 100, 100, 110 // if +3: i <- 100, i+1 <- 100, i+2 <- 110 // if +2: i <- 100, i+1 <- 100, i+2 <- 001 // if +1: i <- 100, i+1 <- 010 // if +0: i <- 010 // we need to cross out 2*n characters in total // so we just need to always cross out at least two characters with each query // problem is when we have 110, 110 // maybe we cross out more than two at the start? // a has 111, b has 111, c has 111 // try 110, 110, 110 // if +3: a <- 110, b <- 110, c <- 110 // if +2: a <- 110, b <- 110, c <- 001 // if +1: a <- 110, b <- 001 // if +0: a <- 001 // P(+3) = 2/3 * 2/3 * 2/3 // P(+2) = 2/3 * 2/3 * 1/3 // P(+1) = 2/3 * 1/3 // P(+0) = 1/3 // C(n) = 2 + n // P(n) = 1/3 * (2/3)^n // M(n) = P(0) * C(0) + P(1) * C(1) + ... + P(n-1) * C(n-1) + 3 * P(n) * (C(n) - 2) // M(n) - 3 * P(n) * (C(n) - 2) // y = sum a^n // a * y = sum a^(n+1) = y + a^(n+1) - a^0 // a * y - y = a^(n+1) - a^0 // y * (a - 1) = a^(n+1) - a^0 // y = (a^(n+1) - 1) / (a - 1) // for 111, 111, 111, ... // M(n) - 3 * P(n) * (C(n) - 2) > 3n // M(n) > 3n + 3 * P(n) * (C(n) - 2) = 3n + n * (2/3)^n // M(n) > 3n // m * 2^l = 8000 // 2^l = 8000 / m // l = log2(8000 / m) // if m = 1 we have l = 12 // afaik we can reduce to only 110s very fast // with randomized algorithm :) // for 110, 110, 110, ... // possible in at most O(n) queries

컴파일 시 표준 에러 (stderr) 메시지

combo.cpp: In function 'std::string guess_sequence(int)':
combo.cpp:81:31: warning: comparison of integer expressions of different signedness: 'int' and 'std::__cxx11::basic_string<char>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
   81 |             for (int i = 0; i < q.size(); i++) {
      |                             ~~^~~~~~~~~~
combo.cpp:50:13: warning: unused variable 'size' [-Wunused-variable]
   50 |         int size = 0;
      |             ^~~~
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