Submission #402576

#TimeUsernameProblemLanguageResultExecution timeMemory
402576blueHarbingers (CEOI09_harbingers)C++17
0 / 100
455 ms42580 KiB
#include <iostream> #include <vector> #include <fstream> using namespace std; /* Let anc[u][x] be the x'th ancestor of u. dp[u] =def= amount of time needed for message to be delivered from u to 1. dp[1] =def= 0 dp[u] = min{S[u] + V[u]*dist(u, v) + dp[v] | v in anc[u]} = min{S[u] + V[u]*(dist1[u] - dist1[v]) + dp[v] | v in anc[u]} dp[u] min= S[u] + V[u]*dist1[u] + -dist1[v]*V[u] + dp[v] a * x + b */ long long INF = 2'000'000'000'000'000'000; vector<long long> edge[100001], dist[100001]; //edges, weights of edges vector<long long> S(100001, 0), V(100001, 0); //starting time, reciprocal speed vector<long long> dist1(100001, 0); long long cht_anc[100001][19]; vector<long long> prev_node(100001); vector<long long> prev_dist(100001); void dfs1(long long u) { for(long long i = 0; i < edge[u].size(); i++) { long long v = edge[u][i]; long long d = dist[u][i]; if(prev_node[u] == v) continue; prev_node[v] = u; prev_dist[v] = d; dist1[v] = dist1[u] + prev_dist[v]; dfs1(v); } } vector<long long> a(100001), b(100001); vector<long long> dp(100001); // long long a(long long u) // { // return -dist1[u]; // } // // long long b(long long u) // { // return dp[u]; // } bool intersect_comp(long long e1, long long e2, long long x) { /*a[e1]*x + b[e1] = a[e2]*x + b[e2] x_e = (b[e2] - b[e1])/(a[e1] - a[e2]) */ // cerr << "intersect comp " << e1 << ' ' << e2 << ' ' << double(b[e2] - b[e1])/double(a[e1] - a[e2]) << ' ' << x << ' ' << ((b[e2] - b[e1]) < (a[e1] - a[e2])*x) << '\n'; return (b[e2] - b[e1]) <= (a[e1] - a[e2])*x; //Be very careful with the sign. } bool line_intersect_comp(long long e1, long long e2, long long f1, long long f2) {//intersect(e1, e2) < intersect(f1, f2) // if(e2 == 1) return 1; return (b[e2] - b[e1])*(a[f1] - a[f2]) <= (b[f2] - b[f1])*(a[e1] - a[e2]); } /* i, i+1, L Line i+2 is a good insertion if intersect(i, i+1) < intersect(i+1, i+2) We need to binary search for the largest line i such that intersect(i-1, i) < intersect(i, L) */ void dfs2(long long u) { for(long long v: edge[u]) { if(prev_node[u] == v) continue; /*w is the ideal harbinger for the harbinger from v to go to Using binary lifting, we search for the edge on which f(x) is maximised Let the lines of the ancestors of v, starting from 1 be l1, l2, ... l_q We are finding the value of V[v] We want to find some line i such that intsec(l[i-1], l[i]) <= x <= intsec(l[i], l[i+1]) We want to find the ancestor of highest depth i such that intsec(p[i], i) > V[v] */ cht_anc[v][0] = u; for(long long e = 1; e <= 18; e++) cht_anc[v][e] = cht_anc[ cht_anc[v][e-1] ][e-1]; long long w = v; for(long long e = 18; e >= 0; e--) { long long temp = cht_anc[w][e]; if(intersect_comp(prev_node[temp], temp, V[v]) == 0) w = temp; } while(intersect_comp(prev_node[w], w, V[v]) == 0) w = prev_node[w]; dp[v] = S[v] + V[v]*dist1[v] + a[w]*V[v] + dp[w]; a[v] = -dist1[v]; b[v] = dp[v]; //* // cerr << a[v] << "*x + " << b[v] << "\n"; // cout << v << "( " << V[v] << ") <- " << w << '\n'; /* We want to find the ancestor of highest depth i such that intsec(p[i], i) > intsec(v, i) */ w = v; for(long long e = 18; e >= 0; e--) { long long temp = cht_anc[w][e]; if(line_intersect_comp(prev_node[temp], temp, temp, v) == 0) w = temp; } w = cht_anc[w][0]; cht_anc[v][0] = w; for(long long e = 1; e <= 18; e++) cht_anc[v][e] = cht_anc[ cht_anc[v][e-1] ][e-1]; dfs2(v); } } int main() { long long N; cin >> N; for(long long j = 1; j <= N-1; j++) { long long u, v, d; cin >> u >> v >> d; edge[u].push_back(v); dist[u].push_back(d); edge[v].push_back(u); dist[v].push_back(d); } for(long long i = 2; i <= N; i++) cin >> S[i] >> V[i]; prev_node[1] = 1; prev_dist[1] = 0; dfs1(1); // for(long long i = 1; i <= N; i++) // { // cerr << "i = " << i << ": "; // cerr << S[i] << ' ' << V[i] << ' ' << dist1[i] << " " << prev_node[i] << ' ' << prev_dist[i] << '\n'; // } dp[1] = 0; for(long long e = 0; e <= 18; e++) cht_anc[1][e] = 1; V[1] = S[1] = 0; a[1] = b[1] = 0; dfs2(1); for(long long i = 2; i <= N; i++) cout << dp[i] << ' '; cout << '\n'; }

Compilation message (stderr)

harbingers.cpp: In function 'void dfs1(long long int)':
harbingers.cpp:29:28: warning: comparison of integer expressions of different signedness: 'long long int' and 'std::vector<long long int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
   29 |     for(long long i = 0; i < edge[u].size(); i++)
      |                          ~~^~~~~~~~~~~~~~~~
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