제출 #400944

#제출 시각아이디문제언어결과실행 시간메모리
400944534351From Hacks to Snitches (BOI21_watchmen)C++17
15 / 100
6091 ms173280 KiB
#include <bits/stdc++.h> using namespace std; template<class T, class U> void ckmin(T &a, U b) { if (a > b) a = b; } template<class T, class U> void ckmax(T &a, U b) { if (a < b) a = b; } #define MP make_pair #define PB push_back #define LB lower_bound #define UB upper_bound #define fi first #define se second #define SZ(x) ((int) (x).size()) #define ALL(x) (x).begin(), (x).end() #define FOR(i, a, b) for (auto i = (a); i < (b); i++) #define FORD(i, a, b) for (auto i = (a) - 1; i >= (b); i--) const int MAXN = 250013; const int INF = 1e9 + 7; const int DELTA = 69; typedef long long ll; typedef long double ld; typedef pair<int, int> pii; typedef pair<ll, ll> pll; typedef vector<int> vi; typedef vector<ll> vl; typedef vector<pii> vpi; typedef vector<pll> vpl; int N, M, K; vi edge[MAXN]; pii ban[MAXN]; unordered_map<int, pii> banedge[MAXN]; int dist[MAXN]; bitset<DELTA + 3> seen[MAXN]; priority_queue<pii, vector<pii>, greater<pii> > pq; int32_t main() { cout << fixed << setprecision(12); cerr << fixed << setprecision(4); ios_base::sync_with_stdio(false); cin.tie(0); cin >> N >> M; FOR(i, 0, M) { int u, v; cin >> u >> v; u--; v--; edge[u].PB(v); edge[v].PB(u); } FOR(i, 0, N) { edge[i].PB(i); } cin >> K; FOR(i, 0, K) { int c; cin >> c; vi s(c); FOR(j, 0, c) { cin >> s[j]; s[j]--; ban[s[j]] = {j, c}; } FOR(j, 0, c) { int u = s[j], v = s[(j == c - 1 ? 0 : j + 1)]; banedge[u][v] = {j, c}; banedge[v][u] = {j, c}; // cerr << u << ' ' << v << ' ' << j << ' ' << c << endl; } } fill(dist, dist + N, INF); dist[0] = 0; pq.push({0, 0}); while(!pq.empty()) { int d = pq.top().fi, u = pq.top().se; pq.pop(); if (d - dist[u] >= DELTA) continue; // cerr << d << ' ' << u << endl; if (seen[u][d - dist[u]]) continue; seen[u][d - dist[u]] = true; for (int v : edge[u]) { if (ban[v].se != 0 && (d + 1) % ban[v].se == ban[v].fi) continue; if (banedge[u].count(v) && d % banedge[u][v].se == banedge[u][v].fi) continue; if (dist[v] > d + 1) { dist[v] = d + 1; } // cerr << u << ' ' << v << ' ' << d + 1 << endl; pq.push({d + 1, v}); //you can go from u -> v at time t iff: //t != ban[v].fi mod ban[v].se //t-1 != ban[u][v].fi mod ban[u][v].se } } if (dist[N - 1] >= INF) { cout << "impossible\n"; return 0; } cout << dist[N - 1] << '\n'; return 0; }
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