제출 #40063

#제출 시각아이디문제언어결과실행 시간메모리
40063krauchTorrent (COI16_torrent)C++14
31 / 100
2000 ms68568 KiB
/* _ _ _______ _ _ | | / / | _____| | | / / | | / / | | | | / / | |/ / | |_____ | |/ / | |\ \ | _____| | |\ \ | | \ \ | | | | \ \ | | \ \ | |_____ | | \ \ |_| \_\ |_______| |_| \_\ */ #include <bits/stdc++.h> using namespace std; typedef unsigned long long ull; typedef long long ll; typedef double ld; typedef pair <int, int> PII; typedef pair <ll, ll> PLL; typedef pair < ll, int > PLI; #define F first #define S second #define pb push_back #define eb emplace_back #define right(x) x << 1 | 1 #define left(x) x << 1 #define forn(x, a, b) for (int x = a; x <= b; ++x) #define for1(x, a, b) for (int x = a; x >= b; --x) #define mkp make_pair #define sz(a) (int)a.size() #define all(a) a.begin(), a.end() #define y1 kekekek #define fname "" const ll ool = 1e18 + 9; const int oo = 1e9 + 9, base = 1e9 + 7; const ld eps = 1e-7; const int N = 2e6 + 6; int n, A, B, ans = oo, d[N]; vector < int > g[N], path, vec; bool dfs(int v, int par) { vec.eb(v); if (v == B) path = vec; bool res = 0; vector < int > tmp; for (auto to : g[v]) { if (to == par) continue; bool val = dfs(to, v); res |= val; if (!val) tmp.eb(d[to]); } sort(all(tmp)); reverse(all(tmp)); forn(i, 0, sz(tmp) - 1) { d[v] = max(d[v], tmp[i] + i + 1); } vec.pop_back(); return (res | (v == B)); } int main() { ios_base :: sync_with_stdio(0), cin.tie(0), cout.tie(0); #ifdef krauch freopen("input.txt", "r", stdin); #else //freopen(fname".in", "r", stdin); //freopen(fname".out", "w", stdout); #endif cin >> n >> A >> B; forn(i, 1, n - 1) { int x, y; cin >> x >> y; g[x].eb(y); g[y].eb(x); } dfs(A, 0); forn(i, 0, sz(path) - 2) { int vala = 0; if (!i) { vala = d[A]; } else { vala = d[path[i]]; for1(j, i - 1, 0) { vector < int > tmp; for (auto to : g[path[j]]) { if (to != (j ? path[j - 1] : 0) && to != path[j + 1]) tmp.eb(d[to]); } tmp.eb(vala); sort(all(tmp)); reverse(all(tmp)); vala = 0; forn(k, 0, sz(tmp) - 1) vala = max(vala, tmp[k] + k + 1); } } int valb = 0; if (i == sz(path) - 2) { valb = d[B]; } else { forn(j, i + 1, sz(path) - 1) { vector < int > tmp; for (auto to : g[path[j]]) { if (to != (j ? path[j - 1] : 0) && to != (j < sz(path) - 1 ? path[j + 1] : 0)) tmp.eb(d[to]); } if (j != i + 1) tmp.eb(valb); sort(all(tmp)); reverse(all(tmp)); valb = 0; forn(k, 0, sz(tmp) - 1) valb = max(valb, tmp[k] + k + 1); } } ans = min(ans, max(vala, valb)); } cout << ans << "\n"; return 0; }
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