Submission #399881

#TimeUsernameProblemLanguageResultExecution timeMemory
399881SavicSGrowing Vegetable is Fun 3 (JOI19_ho_t3)C++14
100 / 100
97 ms163040 KiB
#include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> #include <bits/stdc++.h> #define fi first #define se second #define pb push_back #define sz(a) (int)a.size() #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define ff(i,a,b) for(int i=a;i<=b;i++) #define fb(i,b,a) for(int i=b;i>=a;i--) using namespace std; using namespace __gnu_pbds; typedef long long ll; typedef pair<int,int> pii; const int maxn = 405; const int inf = 1e9 + 5; template<typename T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; // os.order_of_key(k) the number of elements in the os less than k // *os.find_by_order(k) print the k-th smallest number in os(0-based) int n; int niz[maxn]; string s; int dp[maxn][maxn][maxn][3]; // 0 - najmanji broj operacija, 1 - zadnja boja int cnt[maxn][3]; vector<int> poz[maxn]; int f(char C){ if(C == 'R')return 0; if(C == 'G')return 1; if(C == 'Y')return 2; assert(false); } int main() { ios::sync_with_stdio(false); cout.tie(nullptr); cin.tie(nullptr); cin >> n >> s; ff(i,0,n - 1)niz[i + 1] = f(s[i]); ff(i,1,n){ ff(j,0,2)cnt[i][j] = cnt[i - 1][j]; cnt[i][niz[i]] += 1; poz[niz[i]].pb(i); } if(max({cnt[n][0], cnt[n][1], cnt[n][2]}) > (n + 1) / 2)return cout << -1, 0; int R = cnt[n][0], G = cnt[n][1], Y = cnt[n][2]; ff(a,0,R)ff(b,0,G)ff(c,0,Y)ff(i,0,2)dp[a][b][c][i] = inf; dp[0][0][0][0] = dp[0][0][0][1] = dp[0][0][0][2] = 0; ff(a,0,R){ ff(b,0,G){ ff(c,0,Y){ ff(i,0,2){ if(a > 0 && i != 0){ // stavaljam R int kol = dp[a - 1][b][c][i]; kol += max(0, cnt[poz[0][a - 1]][1] - b); kol += max(0, cnt[poz[0][a - 1]][2] - c); dp[a][b][c][0] = min(dp[a][b][c][0], kol); } if(b > 0 && i != 1){ int kol = dp[a][b - 1][c][i]; kol += max(0, cnt[poz[1][b - 1]][0] - a); kol += max(0, cnt[poz[1][b - 1]][2] - c); dp[a][b][c][1] = min(dp[a][b][c][1], kol); } if(c > 0 && i != 2){ int kol = dp[a][b][c - 1][i]; kol += max(0, cnt[poz[2][c - 1]][0] - a); kol += max(0, cnt[poz[2][c - 1]][1] - b); dp[a][b][c][2] = min(dp[a][b][c][2], kol); } } } } } int rez = inf; ff(i,0,2)rez = min(rez, dp[R][G][Y][i]); cout << rez << endl; return 0; } /** 6 RRGGYY 2 RG 20 YYGYYYGGGGRGYYGRGRYG 5 RRGYY // probati bojenje sahovski ili slicno **/
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