이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <iostream>
#include <vector>
#define int unsigned long long
using namespace std;
int polar[2]={0,(1LL<<32)-1};
int n;
int v[200001];
class AINT {
vector<int> tree;
int pol;
public:
void reset(int len,int polarity) {
tree=vector<int>(4*len+1,0);
pol=polarity;
}
void construct(int node=1, int cl=1, int cr=n) {
if(cl==cr) {
tree[node]=(v[cl-1]&(polar[pol^(cl&1)]));
}
else {
int mid=(cl+cr)/2;
construct(2*node,cl,mid);
construct(2*node+1,mid+1,cr);
tree[node]=(tree[2*node]^tree[2*node+1]);
}
return;
}
void update(const int poz,const int val, int node=1, int cl=1,int cr=n) {
if(cl==cr) {
tree[node]=(val&(polar[pol^(poz&1)]));
return;
}
int mid=(cl+cr)/2;
if(poz<=mid)
update(poz,val,2*node,cl,mid);
else
update(poz,val,2*node+1,mid+1,cr);
tree[node]=(tree[2*node]^tree[2*node+1]);
//cout << pol <<'\t'<< node <<' ' << cl <<' ' << cr <<' '<< tree[4] <<'\n';
}
int query(const int left,const int right, int node=1, int cl=1, int cr=n) {
//cout << cl << ' '<< cr <<' '<< node <<' ' << tree[node] <<'\n';
if(left<=cl && cr<=right) {
return tree[node];
}
int mid=(cl+cr)/2,ans=0;
if(left<=mid)
ans=query(left,right,2*node,cl,mid);
if(mid<right)
ans^=query(left,right,2*node+1,mid+1,cr);
return ans;
}
} pol1,pol0;
signed main() {
int q;
cin >> n >> q;
for(int i=0; i<n; i++)
cin >> v[i];
pol1.reset(n,1);
pol0.reset(n,0);
pol1.construct();
pol0.construct();
for(int type,x,y,i=0; i<q; i++) {
cin >> type >>x >> y;
if(type==1) {
pol1.update(x,y);
pol0.update(x,y);
}
else {
if(((x^y)&1)==0) {
//cout << "MAATa\n";
if(x&1)
cout << pol0.query(x,y);
else
cout << pol1.query(x,y);
}
else
cout << 0;
cout << '\n';
}
}
return 0;
}
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