# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
397907 | qwerasdfzxcl | 단층 (JOI16_ho_t5) | C++14 | 257 ms | 13596 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
typedef long long ll;
using namespace std;
struct Seg{
ll lazy[400400];
int sz;
void update(int l, int r, ll val){
for(l += sz, r += sz;l<r;l>>=1, r>>=1){
if (l&1) lazy[l++] += val;
if (r&1) lazy[--r] += val;
}
}
ll query(int x){
ll ret = lazy[x+=sz];
for (x>>=1;x;x>>=1) ret += lazy[x];
return ret;
}
}tree1, tree2;
struct Query{
int x, d;
ll l;
}query[200200];
int main(){
int n, q;
scanf("%d %d", &n, &q);
for (int i=0;i<q;i++) scanf("%d %d %lld", &query[i].x, &query[i].d, &query[i].l);
tree1.sz = n, tree2.sz = n;
for (int i=q-1;i>=0;i--){
if (query[i].d==1){
int l = 0, r = n, idx=0;
while(l!=r){
int m = (l+r)/2;
ll tmp = tree1.query(m)*2-m;
if (tmp>-query[i].x){
idx = m+1;
l = m+1;
}
else r = m;
}
//printf("1 %d %d\n", i, idx);
tree2.update(0, idx, -query[i].l);
}
else{
int l = 0, r = n, idx = n;
while(l!=r){
int m = (l+r)/2;
ll tmp = tree2.query(m)*2+m;
if (tmp>=query[i].x){
idx = m;
r = m;
}
else l = m+1;
}
//printf("2 %d %d\n", i, idx);
tree1.update(idx, n, -query[i].l);
}
}
for (int i=0;i<n;i++){
ll ans = tree1.query(i) + tree2.query(i);
printf("%lld\n", -ans);
}
return 0;
}
Compilation message (stderr)
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