이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
// macros
typedef long long ll;
typedef long double ld;
typedef pair<int, int> ii;
typedef pair<ll, ll> lll;
typedef tuple<int, int, int> iii;
typedef vector<int> vi;
typedef vector<ii> vii;
typedef vector<iii> viii;
typedef vector<ll> vll;
typedef vector<lll> vlll;
#define REP(a,b,c) for(int a=int(b); a<int(c); a++)
#define RE(a,c) REP(a,0,c)
#define RE1(a,c) REP(a,1,c+1)
#define REI(a,b,c) REP(a,b,c+1)
#define REV(a,b,c) for(int a=int(c-1); a>=int(b); a--)
#define FOR(a,b) for(auto& a : b)
#define all(a) a.begin(), a.end()
#define INF 1e18
#define EPS 1e-9
#define pb push_back
#define popb pop_back
#define fi first
#define se second
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
// input
template<class T> void IN(T& x) {cin >> x;}
template<class H, class... T> void IN(H& h, T&... t) {IN(h); IN(t...); }
// output
template<class T1, class T2> void OUT(const pair<T1,T2>& x);
template<class T> void OUT(const vector<T>& x);
template<class T> void OUT(const T& x) {cout << x;}
template<class H, class... T> void OUT(const H& h, const T&... t) {OUT(h); OUT(t...); }
template<class T1, class T2> void OUT(const pair<T1,T2>& x) {OUT(x.fi,' ',x.se);}
template<class T> void OUT(const vector<T>& x) {RE(i,x.size()) OUT(i==0?"":" ",x[i]);}
template<class... T> void OUTL(const T&... t) {OUT(t..., "\n"); }
template<class H> void OUTLS(const H& h) {OUTL(h); }
template<class H, class... T> void OUTLS(const H& h, const T&... t) {OUT(h,' '); OUTLS(t...); }
// dp
template<class T> bool ckmin(T&a, T&b) { bool bl = a > b; a = min(a,b); return bl;}
template<class T> bool ckmax(T&a, T&b) { bool bl = a < b; a = max(a,b); return bl;}
void program();
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
program();
}
//===================//
// begin program //
//===================//
const int MX = 5e5;
const int N = (1<<20);
int n, m, a[MX], ra[MX];
int cnt[MX][20];
ll ways[20][2];
void program() {
IN(n); m=(1<<n);
RE(i,m) IN(a[i]);
RE(i,m) ra[a[i]] = i;
ll ans = 1e18;
string ansS, s;
RE(_,n+1) {
s.pb('2');
RE(i,m) ra[i] = (ra[i]>>1)|((ra[i]&1)<<(n-1));
RE(i,m) RE(j,n) cnt[i][j] = 0;
RE(j,n) RE(k,2) ways[j][k] = 0;
REV(i,0,m) RE(j,n) {
int cbm = ra[i]&(~((1<<j)-1));
if(ra[i]&(1<<j)) ways[j][1] += cnt[cbm^(1<<j)][j];
else ways[j][0] += cnt[cbm^(1<<j)][j];
cnt[cbm][j]++;
}
RE(i,m) {
ll cAns = 0;
RE(j,n) cAns += ways[j][i&(1<<j) ? 0 : 1];
if(cAns < ans) {
ans = cAns;
ansS = s;
RE(j,n) {
ansS.pb('2');
if(i&(1<<j)) ansS.pb('1');
}
}
}
}
OUTL(ans);
OUTL(ansS);
}
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