이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
/*
Khangnh's code
“You can either experience the pain of discipline or the pain of regret.
The choice is yours.”
*/
// - Only when necessary :d
// #pragma GCC optimize("Ofast")
// #pragma GCC optimize("unroll-loops")
// #pragma GCC target("avx,avx2,fma")
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
#define fileopen(a, b) freopen(((string)a + ".inp").c_str(), "r", stdin); freopen(((string)b + ".out").c_str(), "w", stdout);
#define ll long long
// #define int long long
#define fi first
#define se second
#define pb push_back
#define pf push_front
#define pob pop_back
#define pof pop_front
typedef pair<int, int> pii;
typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;
const ll mod = 1e9 + 7;
const ll inf = 1e9 + 7;
const double eps = 1e-9;
int n, m;
int a[20], b[20];
pii dp[1 << 20];
void solve() {
cin >> n >> m;
for (int i = 0; i < n; ++i) cin >> a[i];
for (int i = 0; i < m; ++i) cin >> b[i];
dp[0] = {0, 0};
for (int i = 1; i < (1 << m); ++i) {
dp[i] = {0, 0};
for (int j = 0; j < m; ++j) {
if ((i >> j) & 1) {
pii tmp = dp[i ^ (1 << j)];
if (tmp.se + b[j] < a[tmp.fi]) tmp.se += b[j];
else if (tmp.se + b[j] == a[tmp.fi]) ++tmp.fi, tmp.se = 0;
dp[i] = max(dp[i], tmp);
}
}
if (dp[i].first == n) {
cout << "YES";
return;
}
}
cout << "NO";
}
signed main() {
#ifdef khangorz
fileopen("input", "output");
#endif
#ifndef khangorz
// fileopen("LAH", "LAH");
#endif
ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
solve();
return 0;
}
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