Submission #39468

#	Time	Username	Problem	Language	Result	Execution time	Memory
39468		qoo2p5	Palembang Bridges (APIO15_bridge)	C++14	0 / 100	0 ms	2180 KiB

bridge

#include <bits/stdc++.h>

using namespace std;

typedef long long ll;

const int INF = (int) 1e9 + 123;
const ll LINF = (ll) 1e18 + 123;

#define rep(i, s, t) for (auto i = (s); i < (t); ++(i))
#define per(i, s, t) for (auto i = (s); i >= (t); --(i))
#define sz(x) ((int) (x).size())
#define mp make_pair
#define pb push_back
#define all(x) (x).begin(), (x).end()

bool mini(auto &x, const auto &y) {
	if (y < x) {
		x = y;
		return 1;
	}
	return 0;
}

bool maxi(auto &x, const auto &y) {
	if (y < x) {
		x = y;
		return 1;
	}
	return 0;
}

void run();

int main() {
	ios::sync_with_stdio(0);
	cin.tie(0);
	cout.tie(0);
	run();
	return 0;
}

const int N = (int) 1e5 + 123;

int k, n;
vector<pair<ll, ll>> a;
vector<ll> cool;
ll total;

void solve1() {
	int ptr1 = 0, ptr2 = 0;
	vector<ll> p, q;
	ll sum_pl = 0, sum_pr = 0;
	ll sum_ql = 0, sum_qr = 0;
	{
		for (auto &it : a) {
			sum_pr += it.first;
			sum_qr += it.second;
			p.pb(it.first);
			q.pb(it.second);
		}
		sort(all(p));
		sort(all(q));
	}
	
	ll ans = LINF;
	
	for (ll x : cool) {
		while (ptr1 < n && p[ptr1] <= x) {
			sum_pr -= p[ptr1];
			sum_pl += p[ptr1];
			ptr1++;
		}
		while (ptr2 < n && q[ptr2] <= x) {
			sum_qr -= q[ptr2];
			sum_ql += q[ptr2];
			ptr2++;
		}
		ll cur = 0;
		cur += (ptr1 * x - sum_pl) + (sum_pr - (n - ptr1) * x);
		cur += (ptr2 * x - sum_ql) + (sum_qr - (n - ptr2) * x);
		mini(ans, cur);
	}
	
	ans += total;
	cout << ans << "\n";
}

void run() {
	cin >> k >> n;
	rep(i, 0, n) {
		char t1, t2;
		ll x1, x2;
		cin >> t1 >> x1 >> t2 >> x2;
		if (t1 == t2) {
			total += abs(x1 - x2);
		} else {
			if (t1 > t2) {
				swap(t1, t2);
				swap(x1, x2);
			}
			a.pb({x1, x2});
			cool.pb(x1);
			cool.pb(x2);
		}
	}
	sort(all(cool));
	cool.resize(unique(all(cool)) - cool.begin());
	sort(all(a));
	n = sz(a);
	total += n;
	if (k == 1) {
		solve1();
		return;
	}
	
	ll ans = LINF;
	
	for (ll x1 : cool) {
		for (ll x2 : cool) {
			ll cur = 0;
			
			for (auto &it : a) {
				ll best = LINF;
				mini(best, abs(it.first - x1) + abs(it.second - x1));
				mini(best, abs(it.first - x2) + abs(it.second - x2));
				cur += best;
			}
			
			mini(ans, cur);
		}
	}
	
	ans += total;
	cout << ans << "\n";
}

• Subtask 1: 0 / 8
• Subtask 2: 0 / 14
• Subtask 3: 0 / 9
• Subtask 4: 0 / 32
• Subtask 5: 0 / 37