이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int INF = (int) 1e9 + 123;
const ll LINF = (ll) 1e18 + 123;
#define rep(i, s, t) for (auto i = (s); i < (t); ++(i))
#define per(i, s, t) for (auto i = (s); i >= (t); --(i))
#define sz(x) ((int) (x).size())
#define mp make_pair
#define pb push_back
#define all(x) (x).begin(), (x).end()
bool mini(auto &x, const auto &y) {
if (y < x) {
x = y;
return 1;
}
return 0;
}
bool maxi(auto &x, const auto &y) {
if (y < x) {
x = y;
return 1;
}
return 0;
}
void run();
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
run();
return 0;
}
const int N = (int) 1e5 + 123;
int k, n;
vector<pair<ll, ll>> a;
vector<ll> cool;
ll total;
void solve1() {
int ptr1 = 0, ptr2 = 0;
vector<ll> p, q;
ll sum_pl = 0, sum_pr = 0;
ll sum_ql = 0, sum_qr = 0;
{
for (auto &it : a) {
sum_pr += it.first;
sum_qr += it.second;
p.pb(it.first);
q.pb(it.second);
}
sort(all(p));
sort(all(q));
}
ll ans = LINF;
for (ll x : cool) {
while (ptr1 < n && p[ptr1] <= x) {
sum_pr -= p[ptr1];
sum_pl += p[ptr1];
ptr1++;
}
while (ptr2 < n && q[ptr2] <= x) {
sum_qr -= q[ptr2];
sum_ql += q[ptr2];
ptr2++;
}
ll cur = 0;
cur += (ptr1 * x - sum_pl) + (sum_pr - (n - ptr1) * x);
cur += (ptr2 * x - sum_ql) + (sum_qr - (n - ptr2) * x);
mini(ans, cur);
}
ans += total;
cout << ans << "\n";
}
void run() {
cin >> k >> n;
rep(i, 0, n) {
char t1, t2;
ll x1, x2;
cin >> t1 >> x1 >> t2 >> x2;
if (t1 == t2) {
total += abs(x1 - x2);
} else {
if (t1 > t2) {
swap(t1, t2);
swap(x1, x2);
}
a.pb({x1, x2});
cool.pb(x1);
cool.pb(x2);
}
}
sort(all(cool));
cool.resize(unique(all(cool)) - cool.begin());
sort(all(a));
n = sz(a);
total += n;
if (k == 1) {
solve1();
return;
}
}
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