제출 #394569

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
394569		AmineWeslati	카니발 티켓 (IOI20_tickets)	C++14	25 / 100	3095 ms	119516 KiB

tickets

#ifndef LOCAL
#include "tickets.h"
#endif
#include "bits/stdc++.h"
using namespace std;

typedef long long ll;
typedef vector<int> vi;
typedef pair<int,int> pi;
#define pb push_back
#define se second
#define fi first
#define FOR(i,a,b) for (int i = (a); i < (b); ++i)
#define ROF(i,a,b) for (int i = (b-1); i >= (a); --i)

template<class T> bool ckmin(T& a, const T& b) { return a > b ? a = b, 1 : 0; }
template<class T> bool ckmax(T& a, const T& b) { return a < b ? a = b, 1 : 0; }

const ll INF=1e18;
const int MX=1500+10;

//------------------------------------------------------------//

int N,M,K,X[MX][MX]; 

void allocate(vector<vi>ans){
	#ifndef LOCAL
	allocate_tickets(ans);
	return;
	#endif

	FOR(i,0,N) FOR(j,0,M) cout << ans[i][j] << " \n"[j==M-1];
}

ll find_maximum(int K, vector<vi> X) {
	N = X.size();
	M = X[0].size();
	::K=K;

	ll val=0;
	vector< pair<int,pi> >vec;
	FOR(i,0,N) FOR(j,0,M){
		::X[i][j]=X[i][j];
		vec.pb({X[i][j],{i,j}});
		val+=X[i][j];
	}
	sort(vec.begin(),vec.end());

	int a[N][M]; memset(a,0,sizeof(a));
	FOR(i,0,(N*K)/2){
		int x=vec[i].se.fi,y=vec[i].se.se,v=vec[i].fi;
		a[x][y]=1;
		val-=v*2;
	}

	vector<vi>ans;
	ans.resize(N);
	FOR(i,0,N){
		ans[i].assign(M,-1);
	}

	int k=0;
	FOR(i,0,N){

		set<int>s;
		FOR(j,0,K) s.insert(j);

		FOR(j,0,M) if(a[i][j]){
			ans[i][j]=k;
			s.erase(k);
			k++; k%=K;
		}

		FOR(j,0,M) if(!a[i][j]){
			auto it=s.begin();
			ans[i][j]=*it;
			s.erase(it);
		}
	}
	

	allocate(ans);
	

	return val; 
}

//-------------------------------------------------------------//
void IO() {
#ifdef LOCAL
    freopen("input.txt", "r", stdin); 
    freopen("output.txt", "w", stdout);
#endif
}
#ifdef LOCAL
int main(){
	IO();

	int N,M,K; cin>>N>>M>>K;
	vector<vi>a;
	a.resize(N);
	FOR(i,0,N){
		a[i].resize(M);
		FOR(j,0,M) cin>>a[i][j];
	}

	cout << find_maximum(K,a) << endl;
}
#endif

/*
4 2 1
5 9
1 4
3 6
2 7
*/

• Subtask 1: 11 / 11
• Subtask 2: 0 / 16
• Subtask 3: 0 / 14
• Subtask 4: 14 / 14
• Subtask 5: 0 / 12
• Subtask 6: 0 / 23
• Subtask 7: 0 / 10