이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <bits/stdc++.h>
#define fi first
#define se second
#define pb push_back
#define sz(a) (int)a.size()
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define ff(i,a,b) for(int i=a;i<=b;i++)
#define fb(i,b,a) for(int i=b;i>=a;i--)
using namespace std;
using namespace __gnu_pbds;
typedef long long ll;
typedef pair<int,int> pii;
const int maxn = 100005;
const int inf = 1e9 + 5;
template<typename T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
// os.order_of_key(k) the number of elements in the os less than k
// *os.find_by_order(k) print the k-th smallest number in os(0-based)
int n, q;
int niz[maxn];
const int N = (int)1e6 + 5;
ll dud[N];
void upd(int x, ll val) {
while(x <= N) {
dud[x] += val;
x += x&(-x);
}
}
ll query(int x) {
ll sum = 0;
while(x > 0) {
sum += dud[x];
x -= x&(-x);
}
return sum;
}
int main()
{
ios::sync_with_stdio(false);
cout.tie(nullptr);
cin.tie(nullptr);
cin >> n >> q;
ff(i,1,n)cin >> niz[i];
ff(i,1,n - 1) {
int mn = min(niz[i], niz[i + 1]);
int mx = max(niz[i], niz[i + 1]);
upd(mn, 1);
upd(mx + 1, -1);
}
while(q--) {
int tip;
cin >> tip;
if(tip == 1) {
int pos, val;
cin >> pos >> val;
if(pos > 1) {
upd(min(niz[pos - 1], niz[pos]), -1);
upd(max(niz[pos - 1], niz[pos]) + 1, 1);
}
if(pos < n) {
upd(min(niz[pos], niz[pos + 1]), -1);
upd(max(niz[pos], niz[pos + 1]) + 1, 1);
}
niz[pos] = val;
if(pos > 1) {
upd(min(niz[pos - 1], niz[pos]), 1);
upd(max(niz[pos - 1], niz[pos]) + 1, -1);
}
if(pos < n) {
upd(min(niz[pos], niz[pos + 1]), 1);
upd(max(niz[pos], niz[pos + 1]) + 1, -1);
}
}
if(tip == 2) {
int H;
cin >> H;
cout << query(H) << endl;
}
}
return 0;
}
/**
3 3
1 5 1
2 3
1 1 5
2 3
// probati bojenje sahovski ili slicno
**/
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