제출 #393312

#제출 시각아이디문제언어결과실행 시간메모리
393312parsabahrami원 고르기 (APIO18_circle_selection)C++17
7 / 100
3060 ms9172 KiB
/* There's someone in my head but it's not me */ #include <bits/stdc++.h> using namespace std; typedef long long int ll; typedef pair<int, int> pii; #define SZ(x) (int) x.size() #define F first #define S second const int N = 3e5 + 10, MOD = 1e9 + 7; int n, X[N], Y[N], R[N], ord[N], ret[N]; int intersect(int i, int j) { ll x1 = X[i], x2 = X[j], y1 = Y[i], y2 = Y[j], r1 = R[i], r2 = R[j]; return x1 * x1 + x2 * x2 + y1 * y1 + y2 * y2 - r1 * r1 - r2 * r2 <= 2 * (r1 * r2 + x1 * x2 + y1 * y2); } void sub1() { for (int _ = 1; _ <= n; _++) { int i = ord[_]; if (ret[i]) continue; ret[i] = i; for (int j = _ + 1; j <= n; j++) { if (!ret[ord[j]] && intersect(i, ord[j])) ret[ord[j]] = i; } } for (int i = 1; i <= n; i++) printf("%d ", ret[i]); printf("\n"); exit(0); } int main() { scanf("%d", &n); for (int i = 1; i <= n; i++) scanf("%d%d%d", &X[i], &Y[i], &R[i]); iota(ord + 1, ord + n + 1, 1); sort(ord + 1, ord + n + 1, [&] (int i, int j) { return R[i] == R[j] ? i < j : R[i] > R[j]; }); if (n * n <= 1e8) sub1(); set<pair<ll, int>, greater<pair<ll, int>>> st; for (int i = 1; i <= n; i++) st.insert({X[i] + R[i], i}); for (int _ = 1; _ <= n; _++) { int i = ord[_]; if (ret[i]) continue; ret[i] = i; st.erase({X[i] + R[i], i}); while (SZ(st) && st.begin()->F >= X[i] - R[i]) { ret[st.begin()->S] = i; st.erase(st.begin()); } } for (int i = 1; i <= n; i++) printf("%d ", ret[i]); printf("\n"); return 0; }

컴파일 시 표준 에러 (stderr) 메시지

circle_selection.cpp: In function 'int main()':
circle_selection.cpp:37:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   37 |     scanf("%d", &n);
      |     ~~~~~^~~~~~~~~~
circle_selection.cpp:39:14: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   39 |         scanf("%d%d%d", &X[i], &Y[i], &R[i]);
      |         ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
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