제출 #393081

#제출 시각아이디문제언어결과실행 시간메모리
393081SavicSXOR (IZhO12_xor)C++14
100 / 100
128 ms37812 KiB
#include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> #include <bits/stdc++.h> #define fi first #define se second #define pb push_back #define sz(a) (int)a.size() #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define ff(i,a,b) for(int i=a;i<=b;i++) #define fb(i,b,a) for(int i=b;i>=a;i--) using namespace std; using namespace __gnu_pbds; typedef long long ll; typedef pair<int,int> pii; const int maxn = 250005; const int inf = 1e9 + 5; template<typename T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; // os.order_of_key(k) the number of elements in the os less than k // *os.find_by_order(k) print the k-th smallest number in os(0-based) int n, X; int niz[maxn]; int pref[maxn]; int idx = 0; int najm[20 * maxn]; int lipa[20 * maxn][2]; void add(int A, int id) { int tr = 0; fb(mask,30,0) { int bt = 0; if(A & (1ll << mask))bt = 1; if(lipa[tr][bt] == 0)lipa[tr][bt] = ++idx; tr = lipa[tr][bt]; najm[tr] = min(najm[tr], id); } } int kve(int A) { int tr = 0; int mn = inf; bool ok = 1; fb(mask,30,0) { int btA = 0; if(A & (1ll << mask))btA = 1; int btX = 0; if(X & (1ll << mask))btX = 1; // cout << "btA: " << btA << endl; // cout << "btX: " << btX << endl; if(btA == 1) { if(btX == 1) { if(lipa[tr][0] == 0) { ok = 0; break; } tr = lipa[tr][0]; } else { int ntr = lipa[tr][0]; if(ntr != 0) { mn = min(mn, najm[ntr]); } if(lipa[tr][1] == 0) { ok = 0; break; } tr = lipa[tr][1]; } } else { if(btX == 0) { int ntr = lipa[tr][1]; if(ntr != 0) { mn = min(mn, najm[ntr]); } // cout << "ovde: " << endl; if(lipa[tr][0] == 0) { ok = 0; break; } tr = lipa[tr][0]; } else { if(lipa[tr][1] == 0) { ok = 0; break; } tr = lipa[tr][1]; } } // cout << "------------------" << endl; // cout << endl; } if(ok)mn = min(mn, najm[tr]); return mn; } int main() { ios::sync_with_stdio(false); cout.tie(nullptr); cin.tie(nullptr); cin >> n >> X; ff(i,1,n)cin >> niz[i]; ff(i,1,n)pref[i] = pref[i - 1] ^ niz[i]; memset(najm, inf, sizeof(najm)); int rez = 0; int poz = 0; add(0, 0); ff(i,1,n) { // pref[i] ^ pref[j - 1] >= x int pos = kve(pref[i]); if(i - pos > rez) { rez = i - pos; poz = pos + 1; } add(pref[i], i); } cout << poz << " " << rez << endl; return 0; } /** 2 6 6 1 // probati bojenje sahovski ili slicno **/
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