이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <bits/stdc++.h>
#define fi first
#define se second
#define pb push_back
#define sz(a) (int)a.size()
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define ff(i,a,b) for(int i=a;i<=b;i++)
#define fb(i,b,a) for(int i=b;i>=a;i--)
using namespace std;
using namespace __gnu_pbds;
typedef long long ll;
typedef pair<int,int> pii;
const int maxn = 500005;
const int inf = 1e9 + 5;
template<typename T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
// os.order_of_key(k) the number of elements in the os less than k
// *os.find_by_order(k) print the k-th smallest number in os(0-based)
int n;
int niz[maxn];
ll pref[maxn];
int dp[maxn];
int main()
{
ios::sync_with_stdio(false);
cout.tie(nullptr);
cin.tie(nullptr);
cin >> n;
ff(i,1,n)cin >> niz[i];
ff(i,1,n)pref[i] = pref[i - 1] + niz[i];
priority_queue<array<ll,3>, vector<array<ll,3>>, greater<array<ll,3>>> pq;
int mx = 0;
ll sum = 0;
ff(i,1,n) {
while(!pq.empty() && pq.top()[0] <= pref[i]) {
// ovaj koji obrisem on ce za sve vece od i isto vaziti
if(pq.top()[2] >= mx) {
mx = pq.top()[2];
sum = pq.top()[1];
}
pq.pop();
}
dp[i] = mx + 1;
pq.push({1ll * 2 * pref[i] - sum, pref[i], dp[i]});
}
cout << dp[n] << endl;
return 0;
}
/**
9
4 2 9 9 8 8 9 2 10
5
4 3 1 10 4
4
2 3 1 7
5
6 2 3 9 13
3
3 1 2
// probati bojenje sahovski ili slicno
**/
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