이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#include <iostream>
#include <vector>
#include <algorithm>
#include <math.h>
#include <set>
#include <stack>
#include <iomanip>
#include <bitset>
#include <map>
#include <cassert>
#include <array>
#include <queue>
#include <cstring>
#include <random>
#include <unordered_set>
#include <unordered_map>
#define pqueue priority_queue
#define pb(x) push_back(x)
// #define endl '\n'
#define all(x) x.begin(), x.end()
#define int long long
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef vector<int> vi;
typedef vector<vector<int> > vvi;
// typedef tuple<ll, ll, ll> tiii;
typedef pair<int, int> pii;
typedef vector<pair<int, int> > vpii;
typedef vector<bool> vb;
typedef vector<string> vs;
typedef vector<char> vc;
const int inf = 1e9 + 228;
const int infll = 1e18;
const ll mod = 1e9 + 7;
const ll mod2 = 998244353;
const ld eps = 1e-14;
void fast_io(){
ios_base::sync_with_stdio(0);
cin.tie(0);
// freopen("inputik.txt", "r", stdin);
// freopen("outputik.txt", "w", stdout);
}
const int maxn = 2e5 + 228;
int t[maxn*4];
int mx[maxn*4];
int lzupd[maxn*4];
int H[maxn], A[maxn], B[maxn];
int n, q;
int L[maxn], R[maxn];
int ans[maxn];
void push(int v, int l, int r){
if(lzupd[v] != infll){
// cout << 1 << endl;
// cout << v << ": " << t[v] << " -> " << t[v] << endl;
t[v] = max(t[v], mx[v] - lzupd[v]);
if(l != r){
lzupd[v*2] = min(lzupd[v*2], lzupd[v]);
lzupd[v*2+1] = min(lzupd[v*2+1], lzupd[v]);
}
lzupd[v] = infll;
}
}
void upd(int v, int l, int r, int k){
push(v, l, r);
if(l == r){
if(mx[v] == -infll){
mx[v] = H[l];
} else{
mx[v] = -infll;
}
} else{
int mid = (l+r)/2;
if(k <= mid){
upd(v*2, l, mid, k);
} else{
upd(v*2+1, mid+1, r, k);
}
// push(v*2, l, mid);
// push(v*2+1, mid+1, r);
mx[v] = max(mx[v*2], mx[v*2+1]);
// t[v] = max(t[v*2], t[v*2+1]);
}
}
void sett(int v, int l, int r, int ql, int qr, int k){
push(v, l, r);
if(ql <= l && r <= qr){
lzupd[v] = min(lzupd[v], k);
push(v, l, r);
} else if(ql > r || l > qr){
return;
} else{
int mid = (l+r)/2;
sett(v*2, l, mid, ql, qr, k);
sett(v*2+1, mid+1, r, ql, qr, k);
t[v] = max(t[v*2], t[v*2+1]);
// mx[v] = max(mx[v*2], mx[v*2+1]);
}
}
int get(int v, int l, int r, int ql, int qr){
push(v, l, r);
if(ql <= l && r <= qr){
return t[v];
} else if(l > qr || ql > r){
return -1;
} else{
int mid = (l+r)/2;
return max(get(v*2, l, mid, ql, qr), get(v*2+1, mid+1, r, ql, qr));
}
// cout << t[1] << endl;
}
void solve2(){
vvi to_add(n+1);
vvi to_del(n+1);
vvi posts(n+1);
for(int &i:lzupd)
i = infll;
for(int &i:t)
i = -infll;
for(int &i:mx)
i = -infll;
for(int i=0; i<q; i++){
posts[R[i]].pb(i);
}
for(int i=0; i<n; i++){
if(i + A[i] < n){
to_add[i + A[i]].pb(i);
to_del[min(i + B[i] + 1, n)].pb(i);
}
for(int j:to_add[i])
upd(1, 0, maxn, j);
for(int j:to_del[i])
upd(1, 0, maxn, j);
if(i - A[i] >= 0){
sett(1, 0, maxn, max(i - B[i], 0ll), i - A[i], H[i]);
}
for(int j:posts[i]){
// cout << L[j] << " " << R[j] << " " << get(1, 0, maxn, L[j], R[j]) << endl;
ans[j] = max(ans[j], get(1, 0, maxn, L[j], R[j]));
}
}
}
void solve(){
cin >> n;
for(int i=0; i<n; i++){
cin >> H[i] >> A[i] >> B[i];
}
for(int &i:ans)
i = -1;
// int q;
cin >> q;
for(int i=0; i<q; i++){
cin >> L[i] >> R[i];
L[i]--, R[i]--;
}
solve2();
for(int &i:H)
i = -i;
solve2();
for(int i=0; i<q; i++)
cout << ans[i] << endl;
}
/*
5
10 2 4
1 1 1
2 1 3
1 1 1
100 1 1
5
1 2
2 3
1 3
1 4
1 5
=======
20
260055884 2 15
737689751 5 5
575359903 1 15
341907415 14 14
162026576 9 19
55126745 10 19
95712405 11 14
416027186 8 13
370819848 11 14
629309664 4 13
822713895 5 15
390716905 13 17
577166133 8 19
195931195 10 17
377030463 14 17
968486685 11 19
963040581 4 10
566835557 1 12
586336111 6 16
385865831 8 9
1
1 20
*/
signed main(){
fast_io();
// ;(time(NULL));
cout << fixed << setprecision(10);
int q = 1;
// cin >> q;
while(q--)
solve();
}
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