제출 #392170

#제출 시각아이디문제언어결과실행 시간메모리
392170CSQ31수열 (APIO14_sequence)C++14
71 / 100
155 ms131076 KiB
#pragma GCC optimize("Ofast") #include<bits/stdc++.h> using namespace std; #define pb push_back #define fi first #define se second #define sz(a) a.size() #define all(a) a.begin(),a.end() #define lb lower_bound #define ub upper_bound #define owo ios_base::sync_with_stdio(0);cin.tie(0); #define MOD (ll)(1e9+7) #define INF (ll)(1e18) #define debug(...) fprintf(stderr, __VA_ARGS__),fflush(stderr) #define time__(d) for(long blockTime = 0; (blockTime == 0 ? (blockTime=clock()) != 0 : false);\ debug("%s time : %.4fs\n", d, (double)(clock() - blockTime) / CLOCKS_PER_SEC)) typedef long long int ll; typedef long double ld; typedef pair<ll,ll> PII; typedef pair<int,int> pii; typedef vector<vector<int>> vii; typedef vector<vector<ll>> VII; ll gcd(ll a,ll b){if(!b)return a;else return gcd(b,a%b);} const ll is_query = -9223372036854775807; struct line{ ll m,c,id = 0;//y = mx+c line(ll a,ll b,ll d){m = a;c = b;id=d;} ll eval(ll x){return m*x+c;} ld interx(line l) {return (ld)((l.c - c)/(m - l.m));} mutable function<const line*()> succ; //succesor bool operator<(const line &r)const{ if(r.c != is_query)return r.m > m; const line* s = succ(); if (!s) return 0; ll x = r.m; return 1.0L * c - s->c < 1.0L *(s->m - m) * x; //is x greater than the intersection point of s and succ? //if yes then we move forward ez } }; vector<deque<line>>hulls(201); void add(int i,line l){ if(hulls[i].empty()){hulls[i].pb(l);return;} if(hulls[i].front().m == l.m){ if(l.c < hulls[i].front().c)hulls[i].front(); else return; } while(sz(hulls[i])>1){ line a = hulls[i][0]; line b = hulls[i][1]; if((l.c - a.c) *(b.m - a.m)>= (a.c - b.c)*(a.m - l.m))hulls[i].pop_front(); else break; } hulls[i].push_front(l); } PII query(int i,ll x){ while(sz(hulls[i]) > 1 && hulls[i].back().eval(x) < hulls[i][sz(hulls[i])-2].eval(x))hulls[i].pop_back(); return {hulls[i].back().eval(x),hulls[i].back().id}; } int main() { owo int n,k; cin>>n>>k; vector<ll>a(n); for(int i=0;i<n;i++)cin>>a[i]; VII dp(n,vector<ll>(k+1)),par(n,vector<ll>(k+1)); add(0,line(0,0,-1)); vector<ll>p = a; for(int i=1;i<n;i++)p[i]+=p[i-1]; for(int i=0;i<n-1;i++){ for(int j=k;j>=1;j--){ if(hulls[j-1].empty())continue; PII v = query(j-1,p[n-1]-p[i]); dp[i][j] = v.fi + p[i]*(p[n-1] - p[i]); par[i][j] = v.se; //cout<<i<<" "<<j<<" "<<v.se<<'\n'; add(j,line(-p[i],dp[i][j],i)); } } ll ans = 0; for(int i=0;i<n-1;i++){ans = max(ans,dp[i][k]);} //cout<<'\n'; cout<<ans<<'\n'; vector<int>seq; for(int i=0;i<n;i++){ if(dp[i][k] == ans){ int cur = i; for(int j=k;j>=1;j--){ seq.pb(cur); if(cur == -1)break; cur = par[cur][j]; } break; } } reverse(all(seq)); for(int x:seq)cout<<x+1<<" "; }
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