제출 #391261

#제출 시각아이디문제언어결과실행 시간메모리
391261osaaateiasavtnl회문 (APIO14_palindrome)C++14
100 / 100
60 ms69080 KiB
#include <iostream> #include <cstdio> #include <cstdlib> #include <algorithm> #include <cmath> #include <vector> #include <set> #include <map> #include <unordered_set> #include <unordered_map> #include <queue> #include <ctime> #include <cassert> #include <complex> #include <string> #include <cstring> #include <chrono> #include <random> #include <bitset> #include <fstream> using namespace std; #define int long long #define ii pair <int, int> #define app push_back #define all(a) a.begin(), a.end() #define bp __builtin_popcountll #define ll long long #define mp make_pair #define x first #define y second #define Time (double)clock()/CLOCKS_PER_SEC #define debug(x) std::cerr << #x << ": " << x << '\n'; #define FOR(i, n) for (int i = 0; i < n; ++i) #define FORN(i, n) for (int i = 1; i <= n; ++i) #define pb push_back #define trav(a, x) for (auto& a : x) using vi = vector<int>; template <typename T> std::istream& operator >>(std::istream& input, std::vector<T>& data) { for (T& x : data) input >> x; return input; } template <typename T> std::ostream& operator <<(std::ostream& output, const pair <T, T> & data) { output << "(" << data.x << "," << data.y << ")"; return output; } template <typename T> std::ostream& operator <<(std::ostream& output, const std::vector<T>& data) { for (const T& x : data) output << x << " "; return output; } ll div_up(ll a, ll b) { return a/b+((a^b)>0&&a%b); } // divide a by b rounded up ll div_down(ll a, ll b) { return a/b-((a^b)<0&&a%b); } // divide a by b rounded down ll math_mod(ll a, ll b) { return a - b * div_down(a, b); } #define tcT template<class T #define tcTU tcT, class U tcT> using V = vector<T>; tcT> void re(V<T>& x) { trav(a, x) cin >> a; } tcT> bool ckmin(T& a, const T& b) { return b < a ? a = b, 1 : 0; } // set a = min(a,b) tcT> bool ckmax(T& a, const T& b) { return a < b ? a = b, 1 : 0; } ll gcd(ll a, ll b) { while (b) { tie(a, b) = mp(b, a % b); } return a; } const int N = 3e5 + 7, C = 26; int to[N][C], link[N], len[N]; int term[N]; signed main() { #ifdef LOCAL #else #define endl '\n' ios_base::sync_with_stdio(0); cin.tie(0); #endif string s; cin >> s; int n = s.size(); //0 - odd root //1 - even root auto up = [&](int u, int r, char c) { while (u && (r - len[u] < 0 || s[r - len[u]] != c)) u = link[u]; return u; }; len[0] = -1; int ptr = 2; int u = 1; for (int i = 0; i < n; ++i) { int c = s[i] - 'a'; u = up(u, i - 1, s[i]); if (!to[u][c]) { len[ptr] = len[u] + 2; int v = up(link[u], i - 1, s[i]); if (to[v][c]) v = to[v][c]; else v = 1; link[ptr] = v; to[u][c] = ptr; ++ptr; } u = to[u][c]; term[u]++; } for (int i = ptr - 1; i >= 0; --i) { term[link[i]] += term[i]; } int ans = 0; FOR (i, ptr) { ckmax(ans, len[i] * term[i]); } cout << ans << endl; }
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