Submission #3910

#	Time	Username	Problem	Language	Result	Execution time	Memory
3910		imsifile	Hexagon travel (kriii1_H)	C++98	1 / 1	576 ms	1328 KiB

H

#include<stdio.h>
#include<memory.h>
#define md 1000000007

typedef long long ll;

int l, r, m, ty;
ll cmb[2][2222], dy[2][2222][6], t;
// loop type : 0=RGB, 1=RBG, 2=GBR, 3=GRB, 4=BRG, 5=BGR

int main(){
	int i, j, k, x;
	scanf("%d%d%d", &l, &r, &m);
	for(i=0; i<=l+r; i++){
		for(j=0; j<=r; j++){
			if(i<j)break;
			if(i==j || !j)cmb[1-ty][j]=1;
			else{
				cmb[1-ty][j]=cmb[ty][j]+cmb[ty][j-1];
				if(cmb[1-ty][j]>=md)cmb[1-ty][j]-=md;
			}
		}
		ty=1-ty;
	}
	t=cmb[ty][r], ty=0;
	dy[ty][m][4]=1;
	for(i=l+r+m; i>0; i--){
		memset(dy[1-ty],0,sizeof(dy[1-ty]));
		for(j=m; j>=0; j--){
			if(i<j)continue;
			for(k=0; k<6; k++){
				if(i-j>0){
					dy[1-ty][j][k^1]+=dy[ty][j][k];
					if(dy[1-ty][j][k^1]>=md)dy[1-ty][j][k^1]-=md;
				}
				if(j>0){
					if(k%2)x=(k+4)%6;
					else x=(k+2)%6;
					dy[1-ty][j-1][x]+=dy[ty][j][k];
					if(dy[1-ty][j-1][x]>=md)dy[1-ty][j-1][x]-=md;
				}
			}
		}
		ty=1-ty;
	}
	for(i=0; i<3; i++)printf("%lld\n", t*(dy[ty][0][2*i]+dy[ty][0][2*i+1])%md);
	return 0;
}

• Subtask 1: 1 / 1