제출 #390439

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
390439		ponytail	Aliens (IOI16_aliens)	C++17	4 / 100	1 ms	332 KiB

aliens

#include "bits/stdc++.h"
#define int long long
#define fi first
#define se second
#define pb push_back
using namespace std;
const int BIG = 1e18;
const int is_query = -BIG;
struct line {
    int m, b;
    mutable function<const line*()> succ;
    bool operator<(const line& rhs) const {
        if (rhs.b != is_query) return m < rhs.m;
        const line* s = succ();
        if (!s) return 0;
        int x = rhs.m;
        return b - s->b < (s->m - m) * x;
    }
};
struct dynamic_hull : public multiset<line> {
   const int inf = BIG;
   bool bad(iterator y) {
       auto z = next(y);
       if (y == begin()) {
           if (z == end()) return 0;
           return y->m == z->m && y->b <= z->b;
       }
       auto x = prev(y);
       if (z == end()) return y->m == x->m && y->b <= x->b;
       int v1 = (x->b - y->b);
       if (y->m == x->m) v1 = x->b > y->b ? inf : -inf;
       else v1 /= (y->m - x->m);
       int v2 = (y->b - z->b);
       if (z->m == y->m) v2 = y->b > z->b ? inf : -inf;
       else v2 /= (z->m - y->m);
       return v1 >= v2;
   }
   void insert_line(int m, int b) {
       auto y = insert({m,b});
       y->succ = [=] { return next(y) == end() ? 0 : &*next(y); };
       if (bad(y)) { erase(y); return; }
       while (next(y) != end() && bad(next(y))) erase(next(y));
       while (y != begin() && bad(prev(y))) erase(prev(y));
   }
   int eval(int x) {
       auto l = *lower_bound((line) { x, is_query });
       return l.m * x + l.b;
   }
};
int N,M,K;
int take_photos(signed N, signed M,signed K,vector<signed>r, vector<signed>c){
    int occupied[M][M];
    for(int i=0;i<M;i++){
        for(int j=0;j<M;j++){
            occupied[i][j]=0;
        }
    }
    for(int i=0;i<N;i++){
        for(int j=min(r[i],c[i]);j<=max(r[i],c[i]);j++){
            for(int k=min(r[i],c[i]);k<=max(r[i],c[i]);k++){
                occupied[j][k]=1;
            }
        }
    }
    int ans=0;
    for(int i=0;i<M;i++){
        for(int j=0;j<M;j++){
            ans+=occupied[i][j];
        }
    }
    return ans;
}

• Subtask 1: 4 / 4
• Subtask 2: 0 / 12
• Subtask 3: 0 / 9
• Subtask 4: 0 / 16
• Subtask 5: 0 / 19
• Subtask 6: 0 / 40