이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "rect.h"
#include <bits/stdc++.h>
using namespace std;
vector<int> lg{-1};
struct RMQ {
vector<vector<int>> sp;
void init (vector<int> &a) {
int n = a.size();
sp.resize(lg[n]+1, vector<int>(n));
sp[0] = a;
for (int i = 1; i < lg[n]+1; ++i) {
for (int j = 0; j < n - (1 << i) + 1; ++j) {
sp[i][j] = max(sp[i - 1][j], sp[i - 1][j + (1 << (i - 1))]);
}
}
}
int query (int l, int r) {
assert(r >= l);
int k = lg[r-l+1];
return max(sp[k][l], sp[k][r - (1 << k) + 1]);
}
};
struct RMQ2 {
vector<vector<int>> sp;
void init (vector<int> &a) {
int n = a.size();
sp.resize(lg[n]+1, vector<int>(n));
sp[0] = a;
for (int i = 1; i < lg[n]+1; ++i) {
for (int j = 0; j < n - (1 << i) + 1; ++j) {
sp[i][j] = min(sp[i - 1][j], sp[i - 1][j + (1 << (i - 1))]);
}
}
}
int query (int l, int r) {
assert(r >= l);
int k = lg[r-l+1];
return min(sp[k][l], sp[k][r - (1 << k) + 1]);
}
};
long long count_rectangles(vector<vector<int>> a) {
int n = a.size(), m = a[0].size();
int left[n][m], right[n][m];
for (int i = 0; i < n; ++i) {
stack<int> st;
for (int j = 0; j < m; ++j) {
while (st.size() && a[i][st.top()] < a[i][j]) {
st.pop();
}
left[i][j] = st.size() ? st.top() + 1 : 0;
st.push(j);
}
}
for (int i = 0; i < n; ++i) {
stack<int> st;
for (int j = m - 1; ~j; --j) {
while (st.size() && a[i][st.top()] < a[i][j]) {
st.pop();
}
right[i][j] = st.size() ? st.top() - 1 : m - 1;
st.push(j);
}
}
for (int i = 1; i <= n; ++i) {
lg.push_back(lg.back()+!(i&(i-1)));
}
RMQ col[m];
for (int j = 1; j < m - 1; ++j) {
vector<int> p(n);
for (int i = 0; i < n; ++i) {
p[i] = a[i][j];
}
col[j].init(p);
}
RMQ2 R[m];
RMQ L[m];
for (int j = 0; j < m; ++j) {
vector<int> p(n);
for (int i = 0; i < n; ++i) {
p[i] = left[i][j];
}
L[j].init(p);
for (int i = 0; i < n; ++i) {
p[i] = right[i][j];
}
R[j].init(p);
}
long long ans = 0;
for (int x = 1; x < n - 1; ++x) {
for (int y = 1; y < m - 1; ++y) {
for (int i = x; i < n - 1; ++i) {
if (a[i][y] >= a[i][y - 1] || a[i][y] >= a[x - 1][y]) {
break;
}
bool bad = 0;
int limit = min(m - 1, R[y - 1].query(x, i) + 1);
for (int j = y; j < limit && !bad; ++j) {
bool good = L[j + 1].query(x, i) <= y;
int mx = col[j].query(x, i);
good &= mx < a[i + 1][j] && mx < a[x - 1][j];
bad |= mx >= a[x - 1][j] || mx >= a[i + 1][j];
ans += good;
}
}
}
}
return ans;
}
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