| # | Time | Username | Problem | Language | Result | Execution time | Memory | 
|---|---|---|---|---|---|---|---|
| 390332 | oleksg | Robot (JOI21_ho_t4) | C++11 | 0 ms | 0 KiB | 
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#pragma GCC optimize("O2")
#include <fstream>
#include <string>
#include <iostream>
#include <bitset>
#include <math.h>
#include <string>
#include <algorithm>
#include <assert.h>
#include <bits/stdc++.h>
#include <vector>
#include <queue>
#include<stdio.h>
#include<ctype.h>
#define ll long long
using namespace std;
ll n, m;
struct con{
    ll d;
    ll color;
    ll cost;
};
vector<con> cons[100001];
unordered_map<int, ll> cost[100001];
// how much to convert all nodes of a color to some other color
unordered_map<int, ll> dist[100001];
ll dist2[100001];
unordered_map<int, int> used[100001];
//if node with color x was used
int main(){
    cin.tie(0)->sync_with_stdio(0);
    cin >> n >> m;
    int one, two, thre
    ll four;
    for (int x = 0; x < m; x++){
        cin >> one >> two >> three >> four;
        cons[one - 1].push_back({two - 1, three, four});
        cons[two - 1].push_back({one - 1, three, four});
    }
    for (int x = 0; x < n; x++){
        for (int y = 0; y < cons[x].size(); y++){
            int col = cons[x][y].color;
            ll cst = cons[x][y].cost;
            if (cost[x].find(col) == cost[x].end()){
                cost[x][col] = cst;
            } else {
                cost[x][col] += cst;
            }
        }
        dist2[x] = 1e18;
    }
    priority_queue<tuple<ll, int, int>> q;
    //cost, node, color
    q.push(make_tuple(0, 0, 0));
    dist2[0] = 0;
    while(q.size() > 0){
        int node;
        ll cst;
        int color;
        tie(cst, node, color) = q.top();
        cst *= -1;
        q.pop();
        if (node == n - 1 && color == 0){
            break;
        }
        if (used[node].find(color) == used[node].end()){
            used[node][color] = 1;
            if (color != 0){
                //we need to go to a node with the same color
                for (auto con: cons[node]){
                    if (con.color == color){
                        if (used[con.d].find(0) == used[con.d].end()){
                            ll ncost = cst + cost[node][color] - con.cost;
                            if (dist2[con.d] > ncost){
                                dist2[con.d] = ncost;
                                q.push(make_tuple(-1 * ncost, con.d, 0));
                            }
                        }
                    }
                }
            }
            else{
                //there are 3 things which we can do
                for (auto con: cons[node]){
                    //switch everything but the connection
                    ll ncost = cst + cost[node][con.color] - con.cost;
                    if (dist2[con.d] > ncost){
                        dist2[con.d] = ncost;
                        q.push(make_tuple(-1 * ncost, con.d, 0));
                    }
                    //switch our node only
                    ncost = cst + con.cost;
                    if (dist2[con.d] > ncost){
                        dist2[con.d] = ncost;
                        q.push(make_tuple(-1 * ncost, con.d, 0));
                    }
                    //dont switch anything and make the next node switch
                    ncost = cst;
                    if (dist[con.d].find(con.color) == dist[con.d].end() || (dist[con.d][con.color] > ncost && ncost < dist2[con.d] && cost[con.d][con.color] > con.cost)){
                        dist[con.d][con.color] = ncost;
                        q.push(make_tuple(-1 * ncost, con.d, con.color));
                    }
                }
            }
        }
    }
    if (dist2[n - 1] == 1e18){
        cout << -1 << "\n";
    }
    else{
        cout << dist2[n - 1] << "\n";
    }
}
