Submission #388895

#TimeUsernameProblemLanguageResultExecution timeMemory
388895talant117408Bali Sculptures (APIO15_sculpture)C++17
9 / 100
91 ms332 KiB
/*
    Code written by Talant I.D.
*/
#include <bits/stdc++.h>
 
using namespace std;
 
typedef long long ll;
typedef pair <int, int> pii;
typedef pair <ll, ll> pll;
 
#define precision(n) fixed << setprecision(n)
#define pb push_back
#define ub upper_bound
#define lb lower_bound
#define mp make_pair
#define eps (double)1e-9
#define PI 2*acos(0.0)
#define endl "\n"
#define sz(v) int((v).size())
#define all(v) v.begin(),v.end()
#define rall(v) v.rbegin(),v.rend()
#define do_not_disturb ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define OK cout << "OK" << endl;
 
const int mod = 1e9+7;
 
ll mode(ll a) {
    a %= mod;
    if (a < 0) a += mod;
    return a;
}
 
ll subt(ll a, ll b) {
    return mode(mode(a)-mode(b));
}
 
ll add(ll a, ll b) {
    return mode(mode(a)+mode(b));
}
 
ll mult(ll a, ll b) {
    return mode(mode(a)*mode(b));
}
 
ll binpow(ll a, ll b) {
    ll res = 1;
    while (b) {
        if (b&1) res = mult(res, a);
        a = mult(a, a);
        b >>= 1;
    }
    return res;
}

int main() {
	do_not_disturb
	
	int n, a, b;
	cin >> n >> a >> b;
	vector <ll> v(n+1), pref(n+1);
	for (int i = 1; i <= n; i++) cin >> v[i];
	for (int i = 1; i <= n; i++) pref[i] = pref[i-1]+v[i];
	
	if (n <= 20) {
		ll ans = 9e18;
		for (int mask = 0; mask < (1<<n); mask++) {
			ll prev = 1, j = 1, cnt = 0, sum = 0;
			while (j <= n) {
				while (j <= n && !(mask&(1<<(j-1)))) {
					j++;
				}
				if (prev < j) {
					cnt++;
					sum |= pref[j-1]-pref[prev-1];
				}
				prev = j;
				j++;
			}
			if (prev == n) {
				sum |= v[n];
				cnt++;
			}
			if (a <= cnt && cnt <= b) {
				ans = min(ans, sum);
			}
		}
		cout << ans;
	}
	else if (n <= 100 && a == 1) {
		int dp[103][103];
		for (int i = 0; i < 103; i++) {
			for (int j = 0; j < 103; j++) {
				dp[i][j] = 2e9;
			}
		}
		dp[0][0] = 0;
		for (int i = 1; i <= n; i++) {
			for (int orr = 0; orr <= 100; orr++) {
				for (int j = i-1; j >= 0; j--) {
					dp[i][(orr|(pref[i]-pref[j]))] = min(dp[i][(orr|(pref[i]-pref[j]))], 1+dp[j][orr]);
				}
			}
		}
		for (int orr = 0; orr <= 100; orr++) {
			if (dp[n][orr] <= b) {
				cout << orr << endl;
				return 0;
			}
		}
	}
	else if (n <= 100) {
		
	}
	else {
		
	}
	
    return 0;
}
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