제출 #38866

#제출 시각아이디문제언어결과실행 시간메모리
3886614kg말 (IOI15_horses)C++11
17 / 100
183 ms19268 KiB
#include "horses.h" #define MOD 1000000007 #define N 500001 #define NN 1048576 struct NUM { bool big_num; int num; void push(bool _big_num, int _num) { big_num = _big_num, num = _num; } } tree1[NN], one; int n, nn, tree2[NN], Y[N]; NUM mul(NUM x, NUM y) { long long tx = x.num, ty = y.num, temp = (tx*ty) % MOD; NUM res; res.push(tx*ty >= MOD, (int)temp); return res; } long long ll_mul(long long x, long long y) { return x*y; } NUM get_tree1(int lev, int l, int r, int x, int y) { int mid = (l + r) / 2; if (x <= l && r <= y) return tree1[lev]; if (r < x || y < l) return one; return mul(get_tree1(lev * 2, l, mid, x, y), get_tree1(lev * 2 + 1, mid + 1, r, x, y)); } int init(int _n, int *in_x, int *in_y) { NUM temp; n = _n, one.push(false, 1); for (nn = 1; nn < n; nn *= 2); for (int i = 0; i < n; i++) { tree1[nn + i].push(false, in_x[i]); tree2[nn + i] = i + 1; Y[i + 1] = in_y[i]; } for (int i = nn - 1; i >= 1; i--) tree1[i] = mul(tree1[i * 2], tree1[i * 2 + 1]); for (int i = nn - 1; i >= 1; i--) { int l = i * 2, r = i * 2 + 1; temp = get_tree1(1, 1, nn, tree2[l] + 1, tree2[r]); if (temp.big_num || (long long)Y[tree2[l]] <= ll_mul(temp.num, Y[tree2[r]])) tree2[i] = tree2[r]; else tree2[i] = tree2[l]; } long long out = ll_mul(get_tree1(1, 1, nn, 1, tree2[1]).num, Y[tree2[1]]); return (int)(out%MOD); } int updateX(int pos, int val) { return 0; } int updateY(int pos, int val) { return 0; }

컴파일 시 표준 에러 (stderr) 메시지

horses.cpp:58:17: warning: unused parameter 'pos' [-Wunused-parameter]
 int updateX(int pos, int val) { 
                 ^
horses.cpp:58:26: warning: unused parameter 'val' [-Wunused-parameter]
 int updateX(int pos, int val) { 
                          ^
horses.cpp:62:17: warning: unused parameter 'pos' [-Wunused-parameter]
 int updateY(int pos, int val) {
                 ^
horses.cpp:62:26: warning: unused parameter 'val' [-Wunused-parameter]
 int updateY(int pos, int val) {
                          ^
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