Submission #388106

#	Time	Username	Problem	Language	Result	Execution time	Memory
388106		Keshi	Palindromes (APIO14_palindrome)	C++17	73 / 100	1080 ms	23168 KiB

palindrome

//In the name of God
#include <bits/stdc++.h>
using namespace std;

typedef int ll;
typedef pair<ll, ll> pll;

const ll maxn = 3e5 + 100;
const ll mod = 1e9 + 7;
const ll inf = 1e9;

#define fast_io ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
#define file_io freopen("input.txt", "r+", stdin);freopen("output.txt", "w+", stdout);
#define pb push_back
#define Mp make_pair
#define F first
#define S second
#define Sz(x) ll((x).size())
#define all(x) (x).begin(), (x).end()
#define lc (id << 1)
#define rc (lc | 1)

ll n, p[maxn], rnk[maxn], r2[maxn], lcp[maxn];
string s;
ll h;
vector<ll> vec[maxn];

bool cmp(ll i, ll j){
	if(rnk[i] < rnk[j]) return 1;
	if(rnk[i] > rnk[j]) return 0;
	i += h;
	j += h;
	if(i >= n) i -= n;
	if(j >= n) j -= n;
	return (rnk[i] < rnk[j]);
}

ll seg[maxn << 2];

void bld(ll id, ll s, ll e){
	if(e - s == 1){
		seg[id] = lcp[s];
		return;
	}
	ll mid = (s + e) >> 1;
	bld(lc, s, mid);
	bld(rc, mid, e);
	seg[id] = min(seg[lc], seg[rc]);
	return;
}
ll get(ll id, ll s, ll e, ll l, ll r){
	if(r <= s || e <= l) return inf;
	if(l <= s && e <= r) return seg[id];
	ll mid = (s + e) >> 1;
	return min(get(lc, s, mid, l, r), get(rc, mid, e, l, r));
}

int main(){
    fast_io;

	cin >> s;
	s += '#';
	n = Sz(s);
	for(ll i = 0; i < n; i++){
		rnk[i] = ll(s[i] - 'a');
		p[i] = i;
	}
	h = 0;
	sort(p, p + n, cmp);
	r2[p[0]] = 0;
	for(ll i = 1; i < n; i++){
		r2[p[i]] = r2[p[i - 1]];
		if(cmp(p[i - 1], p[i])) r2[p[i]]++;
	}
	for(ll i = 0; i < n; i++){
		rnk[i] = r2[i];
	}
	h = 1;
	while(h < n){
		sort(p, p + n, cmp);
		r2[p[0]] = 0;
		for(ll i = 1; i < n; i++){
			r2[p[i]] = r2[p[i - 1]];
			if(cmp(p[i - 1], p[i])) r2[p[i]]++;
		}
		for(ll i = 0; i < n; i++){
			rnk[i] = r2[i];
		}
		h <<= 1;
	}
	for(ll i = 0, k = 0; i < n; i++){
		if(rnk[i] == n - 1){
			k = 0;
			continue;
		}
		ll j = p[rnk[i] + 1];
		while(i + k < n && j + k < n && s[i + k] == s[j + k]) k++;
		lcp[rnk[i]] = k;
		if(k) k--;
	}
	bld(1, 0, n);
	n--;
	vector<int> d1(n);
	for (int i = 0, l = 0, r = -1; i < n; i++) {
   	 	int k = (i > r) ? 1 : min(d1[l + r - i], r - i + 1);
   	 	while (0 <= i - k && i + k < n && s[i - k] == s[i + k]) {
        k++;
    	}
    	d1[i] = k--;
    	if (i + k > r) {
       	 	l = i - k;
        	r = i + k;
    	}
	}
	vector<int> d2(n);
	for (int i = 0, l = 0, r = -1; i < n; i++) {
   		int k = (i > r) ? 0 : min(d2[l + r - i + 1], r - i + 1);
    	while (0 <= i - k - 1 && i + k < n && s[i - k - 1] == s[i + k]) {
        	k++;
    	}
    	d2[i] = k--;
   		if (i + k > r) {
        	l = i - k - 1;
        	r = i + k;
    	}
	}
	set<ll> st;
	long long ans = 0;
	for(ll i = n; i--;){
		for(ll j : vec[i]){
			st.erase(j);
		}
		vec[i].clear();
		st.insert(i);
		vec[i - d1[i]].pb(i);
		auto it = st.rbegin();
		while(it != st.rend()){
		ll t = (*it - i) * 2 + 1;
		if(t <= lcp[rnk[i] - 1]) break;;
		ll l = rnk[i], r = n + 1;
		while(r - l > 1){
			ll mid = (l + r) >> 1;
			if(get(1, 0, n + 1, rnk[i], mid) >= t) l = mid;
			else r = mid;
		}
		ans = max(ans, (long long)t * (r - rnk[i]));
		it++;
		}
	}
	st.clear();
	for(ll i = n - 1; i--;){
		for(ll j : vec[i]){
			st.erase(j);
		}
		if(d2[i + 1]) st.insert(i);
		if(d2[i + 1]) vec[i - d2[i + 1]].pb(i);
		if(st.empty()) continue;
		auto it = st.rbegin();
		while(it != st.rend()){
		ll t = (*it - i) * 2 + 2;
		if(t <= lcp[rnk[i] - 1]) break;
		ll l = rnk[i], r = n + 1;
		while(r - l > 1){
			ll mid = (l + r) >> 1;
			if(get(1, 0, n + 1, rnk[i], mid) >= t) l = mid;
			else r = mid;
		}
		ans = max(ans, (long long)t * (r - rnk[i]));
		it++;
		}
	}
	cout << ans;

    return 0;
}

• Subtask 1: 8 / 8
• Subtask 2: 15 / 15
• Subtask 3: 24 / 24
• Subtask 4: 26 / 26
• Subtask 5: 0 / 27