제출 #386529

#제출 시각아이디문제언어결과실행 시간메모리
386529Return_0Commuter Pass (JOI18_commuter_pass)C++17
100 / 100
621 ms37868 KiB
#pragma GCC optimize("Ofast,unroll-loops") // #pragma comment(linker, "/stack:200000000") // #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,avx2,fma,tune=native") #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; typedef long long ll; typedef long double ld; typedef pair <ll, ll> pll; #ifdef SINA #define dbg(...) __f(#__VA_ARGS__, __VA_ARGS__) template <typename Arg1> void __f(const char* name, Arg1&& arg1) { cout << name << " : " << arg1 << std::endl; } template <typename Arg1, typename... Args> void __f (const char* names, Arg1&& arg1, Args&&... args) { const char* comma = strchr(names + 1, ',');cout.write(names, comma - names) << " : " << arg1<<" | ";__f(comma+1, args...); } #define dbg2(x, j, n) cout<< #x << " : "; output((j), (n), x, 1); cout.flush(); #else #define dbg(...) 0 #define dbg2(x, j, n) 0 #endif #define SZ(x) ((ll)((x).size())) #define File(s, t) freopen(s ".txt", "r", stdin); freopen(t ".txt", "w", stdout); #define input(j, n, a) for (int _i = (j); _i < (n)+(j); _i++) cin>> a[_i]; #define output(j, n, a, t) for (int _i = (j); _i < (n)+(j); _i++) cout<< a[_i] << (((t) && _i != (n)+(j)-1)? ' ' : '\n'); #define kill(x) return cout<< (x) << endl, 0 #define cl const ll #define fr first #define sc second #define lc (v << 1) #define rc (lc | 1) #define mid ((l + r) >> 1) #define All(x) (x).begin(), (x).end() cl inf = sizeof(ll) == 4 ? (1e9 + 10) : (3e18), mod = 1e9 + 7, MOD = 998244353; template <class A,class B> ostream& operator << (ostream& out,const pair<A,B>&a){return out<<'('<<a.first<<", "<<a.second<<')';} template <class A> ostream& operator << (ostream& out, const vector<A> &a) { out<< '['; for (int i = -1; ++i < int(a.size());) out<< a[i] << (i + 1 < int(a.size()) ? ", " : ""); return out<<']'; } template <class T, typename _t = less <T> > using Tree = tree <T, null_type, _t, rb_tree_tag, tree_order_statistics_node_update>; cl N = 2e5 + 7; ll diss [N], disv [N], disu [N], dpv [N], dpu [N], n, m, S, T, V, U, ans; vector <ll> out [N]; vector <pll> adj [N]; set <pll> st; bool mark [N]; void dijkstra (ll v, ll dis []) { memset(dis, 63, sizeof diss); dis[v] = 0; st.insert({0, v}); while (!st.empty()) { v = st.begin()->sc; st.erase(st.begin()); for (auto [u, w] : adj[v]) if (dis[u] > dis[v] + w) st.erase({dis[u], u}), dis[u] = dis[v] + w, st.insert({dis[u], u}); } } void dfs (cl &v = T) { mark[v] = 1; dpv[v] = disv[v]; dpu[v] = disu[v]; for (auto &u : out[v]) { if (!mark[u]) dfs(u); dpv[v] = min(dpv[v], dpv[u]); dpu[v] = min(dpu[v], dpu[u]); } ans = min(ans, disu[v] + dpv[v]); ans = min(ans, disv[v] + dpu[v]); } int main () { ios::sync_with_stdio(false); cin.tie(0); cout.tie(0); cin>> n >> m >> S >> T >> U >> V; for (ll i = 0, v, u, w; i < m; i++) { cin>> v >> u >> w; adj[v].push_back({u, w}); adj[u].push_back({v, w}); } dijkstra(S, diss); dijkstra(V, disv); dijkstra(U, disu); ans = disv[U]; for (ll v = 1; v <= n; v++) for(auto [u, w] : adj[v]) if (diss[v] == diss[u] + w) out[v].push_back(u); dfs(); cout<< ans << endl; cerr<< "\nTime elapsed: " << 1000 * clock() / CLOCKS_PER_SEC << "ms\n"; return 0; } /* 6 6 1 6 1 4 1 2 1 2 3 1 3 5 1 2 4 3 4 5 2 5 6 1 6 5 1 2 3 6 1 2 1000000000 2 3 1000000000 3 4 1000000000 4 5 1000000000 5 6 1000000000 8 8 5 7 6 8 1 2 2 2 3 3 3 4 4 1 4 1 1 5 5 2 6 6 3 7 7 4 8 8 5 5 1 5 2 3 1 2 1 2 3 10 2 4 10 3 5 10 4 5 10 10 15 6 8 7 9 2 7 12 8 10 17 1 3 1 3 8 14 5 7 15 2 3 7 1 10 14 3 6 12 1 5 10 8 9 1 2 9 7 1 4 1 1 8 1 2 4 7 5 6 16 */
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