제출 #386434

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
386434		ACmachine	Paint By Numbers (IOI16_paint)	C++17	32 / 100	1 ms	396 KiB

paint

#include "paint.h"
#include <bits/stdc++.h>
using namespace std;
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;

template<typename T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
template<typename T, typename U> using ordered_map = tree<T, U, less<T>, rb_tree_tag, tree_order_statistics_node_update>;

typedef long long ll;
typedef long double ld;

typedef pair<int,int> pii;
typedef pair<ll,ll> pll;

typedef vector<int> vi;
typedef vector<ll> vll;

#define FOR(i,j,k,in) for(int i=(j); i < (k);i+=in)
#define FORD(i,j,k,in) for(int i=(j); i >=(k);i-=in)
#define REP(i,b) FOR(i,0,b,1)
#define REPD(i,b) FORD(i,b,0,1)
#define pb push_back
#define mp make_pair
#define ff first
#define ss second
#define all(x) begin(x), end(x)
#define MANY_TESTS int tcase; cin >> tcase; while(tcase--)

const double EPS = 1e-9;
const int MOD = 1e9+7;
const ll INFF = 1e18;
const int INF = 1e9;
const ld PI = acos((ld)-1);
const vi dy = {1, 0, -1, 0, -1, 1, 1, -1};
const vi dx = {0, 1, 0, -1, -1, 1, -1, 1};

void DBG(){cout << "]" << endl;}
template<typename T, typename ...U> void DBG(const T& head, const U... args){ cout << head << "; "; DBG(args...); }
#define dbg(...) cout << "Line(" << __LINE__ << ") -> [" << #__VA_ARGS__ << "]: [", DBG(__VA_ARGS__);
#define chk() cout << "Check at line(" << __LINE__ << ") hit." << endl;

template<class T, unsigned int U>
ostream& operator<<(ostream& out, const array<T, U> &v){out << "[";  REP(i, U) out << v[i] << ", ";  out << "]"; return out;}
template <class T, class U>
ostream& operator<<(ostream& out, const pair<T, U> &par) {out << "[" << par.first << ";" << par.second << "]"; return out;}
template <class T>
ostream& operator<<(ostream& out, const set<T> &cont) { out << "{"; for( const auto &x:cont) out << x << ", "; out << "}"; return out; }
template <class T, class U>
ostream& operator<<(ostream& out, const map<T, U> &cont) {out << "{"; for( const auto &x:cont) out << x << ", "; out << "}"; return out; }
template<class T>
ostream& operator<<(ostream& out, const vector<T> &v){ out << "[";  REP(i, v.size()) out << v[i] << ", ";  out << "]"; return out;}

template<class T>
istream& operator>>(istream& in, vector<T> &v){ for(auto &x : v) in >> x; return in; }


std::string solve_puzzle(std::string s, std::vector<int> c) {
    int k = c.size();
    int n = (int)s.length();
    auto solve_dp = [&](string ts){
        vector<vector<int>> dp(n + 1, vector<int>(k + 1, 0));
        vector<int> ps(n + 1);
        ps[0] = 0;
        FOR(i, 1, n + 1, 1){
            ps[i] += ps[i - 1];
            if(ts[i - 1] != '_')
                ps[i]++;
        }
        dp[0][0] = 1;
        FOR(i, 1, n + 1, 1){
            REP(j, k + 1){
                if(dp[i - 1][j] && ts[i - 1] != 'X')
                    dp[i][j] = 1;
                if(j == 0) continue;
                bool can1 = false;
                int lst = i - c[j - 1];
                if(lst < 0) continue;
                if(lst >= 0 && ps[i] - ps[lst] == c[j - 1])
                    can1 = true;
                bool can2 = false;
                if(lst == 0 || ts[lst - 1] != 'X')
                    can2 = true;
                if(can1 && can2){
                    if(lst == 0){
                        if(j == 1)
                            dp[i][j] = 1;
                    }
                    else if(dp[lst - 1][j - 1])
                        dp[i][j] = 1;
                }
            }
        }
        return dp;
    };
    string ans(n, '?');
    /*
    REP(i, n){
        if(s[i] == 'X')
            ans[i] = 'X';
        else if(s[i] == '_')
            ans[i] = '_';
        else{
            ns[i] = 'X';
            auto dp = solve_dp(ns);
            bool canx = dp[n][k];
            ns[i] = '_';
            dp = solve_dp(ns);
            bool cany = dp[n][k];
            ns[i] = s[i];
            if(canx && !cany)
                ans[i] = 'X';
            else if(cany && !canx)
                ans[i] = '_';
        }
    }
    */
    auto dp1 = solve_dp(s);
    reverse(all(s)); reverse(all(c));
    auto dp2 = solve_dp(s);
    reverse(all(dp2));
    vector<bool> canx(n, false);
    vector<bool> cany(n, false);
    reverse(all(c));
    reverse(all(s));
    REP(i, k){
        int pp = 0;
        REP(j, n - c[i] + 1){
            int right = j + c[i];
            bool can1 = false;
            if(j == 0){
                if(i == 0)
                    can1 = true;
            }
            else{
                if(s[j - 1] != 'X' && dp1[j - 1][i])
                    can1 = true;
            }
            bool can2 = false;
            if(right == n){
                if(i == k - 1)
                    can2 = true;
            }
            else{
                if(s[right] != 'X' && dp2[right + 1][k - (i + 1)])
                    can2 = true;
            }
            if(can1 && can2){
                pp = max(pp, j);
                while(pp < right){
                    canx[pp] = true;
                    pp++;
                }
            }
        }
    }
    REP(i, n){
        REP(j, k + 1){
            if(dp1[i][j] && dp2[i + 1][(k - j)])
                cany[i] = true;
        }
    }
    REP(i, n){
        if(s[i] == 'X')
            ans[i] = 'X';
        else if(s[i] == '_')
            ans[i] = '_';
        else{
            if(canx[i] && !cany[i])
                ans[i] = 'X';
            else if(cany[i] && !canx[i])
                ans[i] = '_';
        }
    }

    return ans;
}

• Subtask 1: 7 / 7
• Subtask 2: 3 / 3
• Subtask 3: 22 / 22
• Subtask 4: 0 / 27
• Subtask 5: 0 / 21
• Subtask 6: 0 / 10
• Subtask 7: 0 / 10