oj.uz

답안 #386279

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
386279 2021-04-06T09:28:17 Z vanic Bootfall (IZhO17_bootfall) C++14
0 / 100
 1 ms 364 KB 
#include <iostream>
#include <cstdio>
#include <cmath>
#include <algorithm>
#include <set>
#include <stack>
#include <vector>
#include <queue>
#include <map>
#include <cstring>
#include <array>
#include <bitset>
#include <cassert>

using namespace std;

const int maxn=505, Log=9, pot=(1<<Log);

bitset < maxn*maxn > potencijal;

int sum;
bitset < maxn*maxn > dp[maxn];
int n;
int br;
int tren;
int p;

void dodaj(int x){
	for(int i=sum; i>=x; --i){
		dp[br][i]=dp[br-1][i-x]|dp[br-1][i];
	}
	for(int i=0; i<x; ++i){
		dp[br][i]=dp[br-1][i];
	}
	br++;
}


void probaj(){
	if(p==2){
		if((tren&1) || !dp[br-1][tren/2]){
			p=0;
		}
		else{
			p=1;
		}
//		cout << "hehe " << p <<  endl;
	}
	else if(p){
		for(int i=1; i<sum; ++i){
			if(!((i+tren)&1) && dp[br-1][(i+tren)/2]){
				potencijal[i]=1;
			}
		}
		p=0;
	}
	else{
		for(int i=0; i<sum; i++){
			if(potencijal[i] && (((i+tren)&1) || !dp[br-1][(i+tren)/2])){
				potencijal[i]=0;
			}
		}
	}
}

vector < int > t[pot*2];
void update(int L, int D, int x, int l, int d, int val){
	if(L>=l && D<=d){
		t[x].push_back(val);
		return;
	}
	if((L+D)/2>=l){
		update(L, (L+D)/2, x*2, l, d, val);
	}
	if((L+D)/2+1<=d){
		update((L+D)/2+1, D, x*2+1, l, d, val);
	}
}
void rokaj(int x){
	for(int i=0; i<(int)t[x].size(); i++){
		tren+=t[x][i];
		dodaj(t[x][i]);
	}
	if(x>=pot){
		if(p==2 || br==n){
			probaj();
		}
		br-=t[x].size();
		for(int i=0; i<(int)t[x].size(); i++){
			tren-=t[x][i];
		}
		return;
	}
	rokaj(x*2);
	rokaj(x*2+1);
	br-=t[x].size();
	for(int i=0; i<(int)t[x].size(); i++){
		tren-=t[x][i];
	}
}

int a[maxn];

int main(){
	ios_base::sync_with_stdio(false);
	cin.tie(0);
	cout.tie(0);
	cin >> n;
	int par=0, nepar=0;
	for(int i=0; i<n; i++){
		cin >> a[i];
		sum+=a[i];
		if(a[i]&1){
			nepar++;
		}
		else{
			par++;
		}
		update(0, pot-1,  1, 0, i, a[i]);
		update(0, pot-1, 1, i+2, pot, a[i]);
	}
	if((par && nepar) || (n&1)){
		cout << 0 << '\n';
		return 0;
	}
	if(par){
		for(int i=1; i<n; i++){
			if(a[i]!=a[i-1]){
				cout << 0 << '\n';
				return 0;
			}
		}
		cout << n/2 << '\n';
		for(int i=1; i<n; i+=2){
			cout << a[0]*i << '\n';
		}
	}
	dp[0][0]=1;
	br=1;
	p=2;
	rokaj(1);
	cout << potencijal.count() << '\n';
	for(int i=0; i<(int)maxn*maxn; i++){
		if(potencijal[i]){
			cout << i << ' ';
		}
	}
	cout << '\n';
	return 0;
}

Subtask #1
0 / 6.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 364 KB Output is correct
2 Correct 1 ms 364 KB Output is correct
3 Correct 1 ms 364 KB Output is correct
4 Incorrect 1 ms 364 KB Output isn't correct
5 Halted 0 ms 0 KB -

Subtask #2
0 / 7.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 364 KB Output is correct
2 Correct 1 ms 364 KB Output is correct
3 Correct 1 ms 364 KB Output is correct
4 Incorrect 1 ms 364 KB Output isn't correct
5 Halted 0 ms 0 KB -

Subtask #3
0 / 15.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 364 KB Output is correct
2 Correct 1 ms 364 KB Output is correct
3 Correct 1 ms 364 KB Output is correct
4 Incorrect 1 ms 364 KB Output isn't correct
5 Halted 0 ms 0 KB -

Subtask #4
0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 364 KB Output is correct
2 Correct 1 ms 364 KB Output is correct
3 Correct 1 ms 364 KB Output is correct
4 Incorrect 1 ms 364 KB Output isn't correct
5 Halted 0 ms 0 KB -

Subtask #5
0 / 21.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 364 KB Output is correct
2 Correct 1 ms 364 KB Output is correct
3 Correct 1 ms 364 KB Output is correct
4 Incorrect 1 ms 364 KB Output isn't correct
5 Halted 0 ms 0 KB -

Subtask #6
0 / 35.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 364 KB Output is correct
2 Correct 1 ms 364 KB Output is correct
3 Correct 1 ms 364 KB Output is correct
4 Incorrect 1 ms 364 KB Output isn't correct
5 Halted 0 ms 0 KB -