이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include "fun.h"
using namespace std;
vector<int> createFunTour(int N, int Q) {
pair<int, int> best = {N, 0};
for(int i = 0; i < N; i++){
int x = attractionsBehind(0, i);
if (x >= (N + 1) / 2)
best = min(best, {x, i});
}
int centroid = best.second;
vector<int> subtreeRoots, distToCentroid(N);
for(int i = 0; i < N; i++){
distToCentroid[i] = hoursRequired(centroid, i);
if (distToCentroid[i] == 1)
subtreeRoots.push_back(i);
}
vector<vector<pair<int, int>>> subtree(subtreeRoots.size());
for(int i = 0; i < N; i++){
if (i == centroid)
continue;
for(int j = 0; j < (int) subtreeRoots.size(); j++)
if (j + 1 == (int) subtreeRoots.size())
subtree[j].push_back({distToCentroid[i], i});
else if (hoursRequired(subtreeRoots[j], i) == distToCentroid[i] - 1){
subtree[j].push_back({distToCentroid[i], i});
break;
}
}
for(auto &v : subtree)
sort(v.begin(), v.end());
vector<int> answer;
int lastSubtree = -1;
for(int i = 0; i < N - 1; i++){
int rem = N - 1 - i;
pair<int, int> best{-1, -1};
for(int j = 0; j < (int) subtreeRoots.size(); j++){
if (subtree[j].empty() || j == lastSubtree)
continue;
bool ok = 1;
for(int k = 0; k < (int) subtreeRoots.size(); k++)
ok &= ((int) subtree[k].size() * 2 <= rem + 1);
if (ok)
best = max(best, {subtree[j].back().first, j});
}
lastSubtree = best.second;
assert(lastSubtree > -1);
answer.push_back(subtree[lastSubtree].back().second);
subtree[lastSubtree].pop_back();
}
answer.push_back(centroid);
return answer;
}
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