제출 #384691

#제출 시각아이디문제언어결과실행 시간메모리
384691anachorAliens (IOI16_aliens)C++14
0 / 100
1 ms364 KiB
#include<bits/stdc++.h> using namespace std; const int N = 1e5+7, K = 55; long long sq(long long z) { return z*z; } long long cost(int l, int r, int *x, int *y, long long c) { // cout<<l<<" "<<r<<" "<<c<<" "<<y[r]<<" "<<x[l]<<" "<<(y[r] - x[l])*(y[r] - x[l]) + c<<endl; return sq(y[r] - x[l]) - sq(max(0, y[l-1] - x[l])) + c; } typedef pair<long long, long long> PLL; PLL dp[N]; PLL operator+(PLL a, PLL b) { return PLL(a.first+b.first, a.second+b.second); } long long opt[N]; int x[N], y[N]; PLL check(long long c, int n, int *x, int *y) { deque<pair<int, int>> dq; dq.push_back({0, 1}); dp[0] = {0, 0}; for (int i=1; i<=n; i++) { opt[i] = dq.front().first; dp[i] = dp[opt[i]] + PLL(cost(opt[i]+1, i, x, y, c), -1); // cout<<i<<" --> "<<opt[i]<<" "<<dp[i].first<<endl; dq[0].second++; if (dq.size() > 1 && dq[0].second == dq[1].second) dq.pop_front(); int en = n; while(dq.size()) { int o = dq.back().first, st = dq.back().second; if (dp[o]+PLL(cost(o+1, st, x, y, c), -1) >= dp[i]+PLL(cost(i+1, st, x, y, c), -1)) dq.pop_back(); else { int lo = st, hi = en; while (lo < hi) { int mid = (lo+hi+1)/2; if (dp[o]+PLL(cost(o+1, mid, x, y, c), -1) < dp[i]+PLL(cost(i+1, mid, x, y, c), -1) ) lo = mid; else hi = mid-1; } if (lo < n) dq.push_back({i, lo+1}); break; } en = st-1; } if (dq.empty()) dq.push_back({i, i+1}); } dp[n].second *= -1; // cout<<c<<" "<<dp[n].first<<" "<<dp[n].second<<endl; return dp[n]; } long long take_photos(int n, int N, int k, vector<int> xx, vector<int> yy) { vector<pair<int, int>> ranges; for (int i=0; i<n; i++) { ranges.push_back({max(xx[i], yy[i]), -min(xx[i], yy[i])}); } sort(ranges.begin(), ranges.end()); vector<pair<int, int>> r2; for (auto pr: ranges) { int r = pr.first, l = -pr.second; while (r2.size() && r2.back().first >= l) r2.pop_back(); r2.push_back({l, r}); } k = n; n = r2.size(); for (int i=1; i<=n; i++) { x[i] = r2[i-1].first, y[i] = r2[i-1].second+1; } long long lo = -1e12, hi = 1e12; while (lo < hi) { long long mid = lo + (hi-lo+1)/2; if (check(mid, n, x, y).second < k) hi = mid-1; else lo = mid; } return check(lo, n, x, y).first - k*lo; }
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