Submission #384511

#	Time	Username	Problem	Language	Result	Execution time	Memory
384511		Peti	Election (BOI18_election)	C++14	0 / 100	4 ms	492 KiB

election

#include <bits/stdc++.h>

using namespace std;

struct segment_tree{
    vector<int> st, stadd;
    int maxn = 0;

    void init(int n){
        maxn = n;
        while(maxn != (maxn&(-maxn))) maxn += (maxn&(-maxn));
        st.assign(2*maxn, 0);
        stadd.assign(2*maxn, 0);
        return;
    }

    void pont_update(int x, int l, int r){
        if(l+1 == r){
            st[x] += stadd[x];
            stadd[x] = 0;
            return;
        }
        st[x] = min(st[2*x+1], st[2*x+2]) + stadd[x];
        return;
    }

    void propagate(int x, int l, int r){
        if(l+1 == r){
            pont_update(x, l, r);
            return;
        }
        int m = (l+r)/2;
        stadd[2*x+1] += stadd[x];
        stadd[2*x+2] += stadd[x];
        stadd[x] = 0;
        pont_update(2*x+1, l, m);
        pont_update(2*x+2, m, r);
        pont_update(x, l, r);
        return;
    }

    void add(int L, int R, int c, int x, int l, int r){
        propagate(x, l, r);
        if(r <= L || R <= l)
            return;
        if(L <= l && r <= R){
            stadd[x] += c;
            pont_update(x, l, r);
            return;
        }
        int m = (l+r)/2;
        add(L, R, c, 2*x+1, l, m);
        add(L, R, c, 2*x+2, m, r);
        return;
    }

    void add(int l, int r, int c){
        add(l, r, c, 0, 0, maxn);
        return;
    }

    int ertek(int L, int R, int x, int l, int r){
        propagate(x, l, r);
        if(r <= L || R <= l)
            return (int)1e9;
        if(L <= l && r <= R)
            return st[x];
        int m = (l+r)/2;
        return min(ertek(L, R, 2*x+1, l, m), ertek(L, R, 2*x+2, m, r));
    }

    int ertek(int l, int r){
        return ertek(l, r, 0, 0, maxn);
    }

    int elem(int ind, int x, int l, int r){
        propagate(x, l, r);
        if(l+1 == r)
            return st[x];
        int m = (l+r)/2;
        if(ind < m)
            return elem(ind, 2*x+1, l, m);
        return elem(ind, 2*x+2, m, r);
    }

    int elem(int x){
        return elem(x, 0, 0, maxn);
    }
};

struct segment_tree2{
    vector<int> st;
    int maxn = 0;

    void init(int n){
        maxn = n;
        while(maxn != (maxn&(-maxn))) maxn += (maxn&(-maxn));
        st.assign(2*maxn, 0);
        return;
    }

    void update(int x, int c){
        st[x+maxn] = c;
        for(int i = (x+maxn)>>1; i > 0; i >>= 1)
            st[i] = st[2*i] + st[2*i+1];
        return;
    }

    int ertek(int L, int R, int x, int l, int r){
        if(r <= L || R <= l)
            return 0;
        if(L <= l && r <= R)
            return st[x];
        return ertek(L, R, 2*x, l, (l+r)/2) + ertek(L, R, 2*x+1, (l+r)/2, r);
    }

    int ertek(int l, int r){
        return ertek(l, r, 1, 0, maxn);
    }
};

int main()
{
    cin.sync_with_stdio(false);
    cin.tie(0);

    int n, q;
    string s;
    cin>>n;
    cin>>s;
    cin>>q;

    vector<vector<pair<int, int>>> v(n);
    for(int i = 0; i < q; i++){
        int l, r;
        cin>>l>>r;
        v[l-1].push_back(make_pair(r-1, i));
    }

    vector<int> kov(n);
    iota(kov.begin(), kov.end(), 1);


    vector<int> ki(q);

    segment_tree st;
    segment_tree2 st3;
    st.init(n+1);
    st3.init(n+1);

    vector<bool> volt(n, false);
    for(int i = 0; i < n; i++){
        if(s[i] == 'C')
            volt[i] = true;
        else
            st3.update(i, 1);
    }

    int x = n-1, last = n-1;
    for(int i = n-1; i >= 0; i--){
        if(s[i] == 'C'){
            x = i;
            while(x < n && volt[x])
                x++;

            if(x < n){
                /*if(last != x)
                    kov[last] = x;*/
                volt[x] = true;
                st3.update(x, 0);
                st.add(0, x+1, -1);
            }
            st.add(0, i+1, 1);
        } else
            x = last = i;
        for(pair<int, int> temp : v[i])
            ki[temp.second] = max(0, st.elem(temp.first+1)-st.ertek(i, temp.first+1)) + st3.ertek(i, temp.first+1);
    }

    for(int x : ki)
        cout<<x<<"\n";

    return 0;
}

• Subtask 1: 0 / 28
• Subtask 2: 0 / 54
• Subtask 3: 0 / 18