Submission #384200

#TimeUsernameProblemLanguageResultExecution timeMemory
384200aryan12구경하기 (JOI13_watching)C++17
100 / 100
249 ms32492 KiB
#include <bits/stdc++.h> using namespace std; #define int long long const int N = 2010; int a[N + 20]; int dp[N + 20][N + 20]; int n; bool Cost(int w, int p, int q) { int forP[n + 1], forQ[n + 1]; for(int i = 0; i <= n; i++) { forP[i] = 0; forQ[i] = 0; } int prev = 1; for(int i = 1; i <= n; i++) { for(int j = prev; j <= n; j++) { if(a[j] - a[i] >= w) { prev = j; break; } else if(j == n) { prev = n + 1; } } forP[i] = prev - 1; } prev = 1; for(int i = 1; i <= n; i++) { for(int j = prev; j <= n; j++) { if(a[j] - a[i] >= 2 * w) { prev = j; break; } else if(j == n) { prev = n + 1; } } forQ[i] = prev - 1; } /*cout << "forP array\n"; for(int i = 1; i <= n; i++) { cout << forP[i] << " "; } cout << "\n"; cout << "forQ array\n"; for(int i = 1; i <= n; i++) { cout << forQ[i] << " "; } cout << "\n";*/ for(int i = 0; i < N; i++) { for(int j = 0; j < N; j++) { dp[i][j] = 0; } } for(int i = 1; i <= p; i++) { dp[i][0] = (dp[i - 1][0] == n) ? dp[i - 1][0] : forP[dp[i - 1][0] + 1]; } for(int j = 1; j <= q; j++) { dp[0][j] = (dp[0][j - 1] == n) ? dp[0][j - 1] : forQ[dp[0][j - 1] + 1]; } for(int i = 1; i <= p; i++) { for(int j = 1; j <= q; j++) { if(dp[i - 1][j] == n || dp[i][j - 1] == n) { dp[i][j] = n; continue; } dp[i][j] = max((forP[dp[i - 1][j] + 1]), (forQ[dp[i][j - 1] + 1])); } } if(dp[p][q] == n) return true; return false; } void Solve() { int p, q; cin >> n >> p >> q; for(int i = 1; i <= n; i++) { cin >> a[i]; } sort(a + 1, a + 1 + n); if(p + q >= n) { cout << "1\n"; return; } int left = 1, right = 1e9; int mid, ans = 1e9 + 1; while(left <= right) { //cout << "left = " << left << ", right = " << right << "\n"; mid = (left + right) / 2; //cout << "mid = " << mid << "\n"; if(Cost(mid, p, q)) { //cout << "mid is coming true\n"; right = mid - 1; ans = mid; } else { //cout << "mid is coming false\n"; left = mid + 1; } } cout << ans << "\n"; } int32_t main() { ios_base::sync_with_stdio(0); cin.tie(0); Solve(); return 0; }
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