이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>
using namespace std;
using namespace __gnu_pbds;
template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>;
#define ll long long int
#define F first
#define S second
#define pb push_back
const ll N = 3e5 + 5;
const ll LOG = 20;
const ll MOD = 1e9 + 7;
const ll INF = 1e9 + 5;
ll dp[20][2][10][10];
// 50 -> tool
// 2 -> koochiktar shode?
// 20 -> raghame yeki moonde be akhar
// 20 raghame akhar
int l[20], r[20], tmp[20], a[20];
inline int pre(ll x){
int cur = -1;
fill(tmp, tmp + 20, 0);
for (int i = 18; i >= 1; i --){
if ((x == 0) && (cur == -1)){
cur = i;
}
tmp[i] = x % 10;
x /= 10ll;
}
fill(a, a + 20, 0);
for (int i = 1; cur + i <= 18; i ++){
a[i] = tmp[cur + i];
}
return 18 - cur;
}
inline ll solve(int s, int e){
if (e - s + 1 == 1){
return a[1] + 1;
}
memset(dp, 0, sizeof dp);
if (a[1] != a[2]){
dp[2][0][a[1]][a[2]] ++;
}
s += 2;
for (int i = 1; i < 10; i ++){
for (int j = 0; j < 10; j ++){
if (i == j) continue;
if (i < a[1] || (i == a[1] && j < a[2])){
dp[2][1][i][j] ++;
}
}
}
for (int n = s; n <= e; n ++){
for (int i = 0; i < 10; i ++){
for (int j = 0; j < 10; j ++){
for (int k = 0; k < 10; k ++){
if (k == j || k == i) continue;
if (k == a[n]){
dp[n][0][j][k] += dp[n - 1][0][i][j];
}
dp[n][1][j][k] += dp[n - 1][1][i][j];
if (k < a[n]){
dp[n][1][j][k] += dp[n - 1][0][i][j];
}
}
}
}
}
ll ret = 0;
for (int i = 0; i < 10; i ++){
for (int j = 0; j < 10; j ++){
ret += dp[e][0][i][j] + dp[e][1][i][j];
}
}
return ret;
}
int main() {
ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);
ll l, r, ans = 0;
cin >> l >> r; l --;
if (r == 0){
cout << 1 << '\n';
return 0;
}
int sz = pre(r);
ans += solve(1, sz);
ll pw10 = 1, a9;
for (int i = 1; i <= 18; i ++){
pw10 *= 10ll;
a9 = pw10 - 1ll;
if (a9 < r){
sz = pre(a9);
ans += solve(1, sz);
}
else {
break;
}
}
if (l == -1) return cout << ans << '\n', 0;
if (l == 0) return cout << ans - 1 << '\n', 0;
sz = pre(l);
ans -= solve(1, sz);
pw10 = 1;
for (int i = 1; i <= 18; i ++){
pw10 *= 10ll;
a9 = pw10 - 1ll;
if (a9 < l){
sz = pre(a9);
ans -= solve(1, sz);
}
else {
break;
}
}
cout << ans << '\n';
return 0;
}
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