이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
//#pragma GCC optimize ("O2,unroll-loops")
//#pragma GCC optimize("no-stack-protector,fast-math")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
using namespace std;
typedef long long ll;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<pii, int> piii;
typedef pair<ll, ll> pll;
#define debug(x) cerr<<#x<<'='<<(x)<<endl;
#define debugp(x) cerr<<#x<<"= {"<<(x.first)<<", "<<(x.second)<<"}"<<endl;
#define debug2(x, y) cerr<<"{"<<#x<<", "<<#y<<"} = {"<<(x)<<", "<<(y)<<"}"<<endl;
#define debugv(v) {cerr<<#v<<" : ";for (auto x:v) cerr<<x<<' ';cerr<<endl;}
#define all(x) x.begin(), x.end()
#define pb push_back
#define kill(x) return cout<<x<<'\n', 0;
const int inf=1000000010;
const ll INF=1000000000000001000LL;
const int mod=1000000007;
const int MAXN=1000010, LOG=20;
int n, m, k, u, v, x, y, t, a, b, ans;
int par[LOG][MAXN], sz[MAXN];
char last[MAXN];
void Init(){
}
void TypeLetter(char ch){
par[0][n+1]=n;
sz[n+1]=sz[n]+1;
last[n+1]=ch;
n++;
if (!last[par[0][n]]) par[0][n]=par[0][par[0][n]];
for (int i=1; i<LOG; i++) par[i][n]=par[i-1][par[i-1][n]];
}
void UndoCommands(int ted){
par[0][n+1]=n-ted;
n++;
if (!last[par[0][n]]) par[0][n]=par[0][par[0][n]];
sz[n]=sz[par[0][n]];
for (int i=1; i<LOG; i++) par[i][n]=par[i-1][par[i-1][n]];
}
char GetLetter(int pos){
int v=n;
for (int i=LOG-1; ~i; i--) if (sz[par[i][v]]>pos) v=par[i][v];
return last[v];
}
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