Submission #38180

#TimeUsernameProblemLanguageResultExecution timeMemory
38180farmersriceCalvinball championship (CEOI15_teams)C++14
60 / 100
1000 ms65536 KiB
#include <bits/stdc++.h> //#pragma GCC optimize ("O3") //#pragma GCC target ("sse4") #pragma GCC target ("avx,tune=native") //Use above if bruteforcing with lots of small operations. Or just use it anytime, there's no downside. AVX is better slightly /* TASK: hidden LANG: C++11 */ using namespace std; typedef long long ll; typedef pair<int, int> pair2; typedef pair<int, pair<int, int> > pair3; typedef pair<int, pair<int, pair<int, int> > > pair4; #define MAXN 10013 #define INF 1000000000000000000LL #define mp make_pair #define add push_back #define remove pop #define MOD 1000007 int n; int values[MAXN]; //int dp[MAXN][MAXN]; //dp[i][j]: num ways from point i IF the highest number that appears before us is j (implying value of i is at most j + 1) //dp[i][j] = dp[i + 1][j] * j + dp[i + 1][j + 1] map<int, map<int, int> > dp; int solve(int index, int first) { if (first < 0 || first > n) return 0; if (first == 0) return dp[index][first] = solve(index + 1, first + 1); if (index == n) return 1; if (dp[index].find(first) != dp[index].end()) { return dp[index][first]; } ll answer = solve(index + 1, first) * first * 1LL + solve(index + 1, first + 1); answer %= MOD * 1LL; return dp[index][first] = (int) answer; } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cin >> n; for (int i = 0; i < n; i++) { cin >> values[i]; } ll answer = 0; int highestNum = 0; for (int i = 0; i < n; i++) { //highestNum = max(highestNum, values[i]); //if (highestNum == 1) continue; answer += (1LL * (values[i] - 1) * solve(i + 1, highestNum)) % MOD; //cout << "solve " << i << " " << min(values[i] - 2, highestNum - 1) << " is " << solve(i, min(values[i] - 2, highestNum - 1)) << endl; answer %= MOD * 1LL; highestNum = max(highestNum, values[i]); } cout << answer + 1 << endl; }
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