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#include <bits/stdc++.h>
#include "gondola.h"
using namespace std;
using tint = long long;
using ld = long double;
#define FOR(i,a,b) for (int i = (a); i < (b); ++i)
#define F0R(i,a) FOR(i,0,a)
#define ROF(i,a,b) for (int i = (b)-1; i >= (a); --i)
#define R0F(i,a) ROF(i,0,a)
#define trav(a,x) for (auto& a: x)
using pi = pair<int,int>;
using pl = pair<tint,tint>;
using vi = vector<int>;
using vpi = vector<pi>;
using vpl = vector<pl>;
using vvi = vector<vi>;
using vl = vector<tint>;
using vb = vector<bool>;
#define pb push_back
#define pf push_front
#define rsz resize
#define all(x) begin(x), end(x)
#define rall(x) x.rbegin(), x.rend()
#define sz(x) (int)(x).size()
#define ins insert
#define f first
#define s second
#define mp make_pair
#define DBG(x) cerr << #x << " = " << x << endl;
const int MOD = 1e9+9; //change this
const tint mod = 998244353;
const int MX = 5005;
const tint INF = 1e18;
const int inf = 2e9;
const ld PI = acos(ld(-1));
const ld eps = 1e-5;
const int dx[4] = {1, -1, 0, 0};
const int dy[4] = {0, 0, 1, -1};
template<class T> void remDup(vector<T> &v){
sort(all(v)); v.erase(unique(all(v)),end(v));
}
template<class T> bool ckmin(T& a, const T& b) {
return b < a ? a = b, 1 : 0;
}
template<class T> bool ckmax(T& a, const T& b) {
return a < b ? a = b, 1 : 0;
}
bool valid(int x, int y, int n, int m){
return (0<=x && x<n && 0<=y && y<m);
}
int cdiv(int a, int b) { return a/b+((a^b)>0&&a%b); } //redondea p arriba
int fdiv(int a, int b) { return a/b-((a^b)<0&&a%b); } //redondea p abajo
void NACHO(string name = ""){
ios_base::sync_with_stdio(0); cin.tie(0);
if(sz(name)){
freopen((name+".in").c_str(), "r", stdin);
freopen((name+".out").c_str(), "w", stdout);
}
}
int valid(int n, int b[])
{
// si algun numero aparece dos veces, no se puede.
// si hay dos numeros <= n (no se cambiaron), hay
// que chequear que sean validos
// si son todos >= n o todos excepto 1, no hay forma de verificar nada.
vi id (n);
vi a (n);
F0R(i, n) a[i] = b[i];
F0R(i, n) id[i] = i+1;
vi c (250005, 0);
F0R(i, n) ++c[a[i]];
F0R(i, 250005) if(c[i] > 1) return 0;
int pos = -1;
F0R(i, n) if(a[i] <= n) pos = i;
if(pos == -1) return 1;
rotate(id.begin(), id.begin()+a[pos]-1, id.end());
rotate(a.begin(), a.begin()+pos, a.end());
F0R(i, n) if(a[i] <= n && a[i] != id[i]) return 0;
return 1;
}
//----------------------
int replacement(int n, int b[], int replacementSeq[])
{
bool allG = 1;
vi id (n);
vi a (n);
F0R(i, n) a[i] = b[i];
F0R(i, n) id[i] = i+1;
F0R(i, n) if(a[i] <= n) allG = 0;
vi c (n);
F0R(i, n) c[i] = a[i];
if(allG){
F0R(i, n) a[i] = i+1;
}
// uso el pivot para saber que gondola cambiada se corresponde
// con que gondola original
int pos;
F0R(i, n) if(a[i] <= n) pos = i;
rotate(id.begin(), id.begin()+a[pos]-1, id.end());
rotate(a.begin(), a.begin()+pos, a.end());
rotate(c.begin(), c.begin()+pos, c.end());
vpi g;
if(allG) F0R(i, n) a[i] = c[i];
F0R(i, n){
if(a[i] > n) g.pb(mp(a[i], i));
}
if(sz(g) == 0) return 0;
sort(all(g));
int ind = 0;
set<int> av;
FOR(i, n+1, 250005) av.ins(i);
F0R(i, n) if(a[i] > n) av.erase(a[i]);
F0R(i, sz(g)){
int cur = id[g[i].s];
while(cur < g[i].f){
replacementSeq[ind] = cur;
cur = *av.begin();
av.erase(*av.begin());
++ind;
}
av.ins(cur);
}
return ind;
}
//----------------------
int add(int a, int b){
return (a+b) % MOD;
}
int sub(int a, int b){
return (a-b+MOD) % MOD;
}
int mul(int a, int b){
return (tint)a * b % MOD;
}
int bexp(int a, int b){
int ret = 1;
a %= MOD;
while(b > 0){
if(b & 1) ret = mul(ret, a);
a = mul(a, a);
b /= 2;
}
return ret;
}
int countReplacement(int n, int b[])
{
if(!valid(n, b)) return 0;
// sea maxi el maximo numero de gondola
// claramente, tengo que insertar
// todas las gondolas entre [n+1;maxi] para
// llegar a maxi.
// ahora, cuantas formas tengo de poner la gondola x?
// puedo ponerla en la cantidad de lugares cuya gondola final
// es mayor a x.
// sin embargo, si vas de n+1 a maxi es a lo sumo 1e9, por lo cual esto
// no es viable.
// lo que hay que notar es lo siguiente.
// supongamos que tenemos ... ... ... 12 29 36
// para todos los numeros entre [12;28], la respuesta es 2.
// por lo tanto, no hace falta iterar poor todos ellos
// ya que su respuesta es la misma (podemos hacer 2^(29-12).
bool allG = 1;
F0R(i, n) if(b[i] <= n) allG = 0;
vi a;
F0R(i, n){
if(b[i] > n) a.pb(b[i]);
}
a.pb(n);
sort(all(a));
int ret = 1;
FOR(i, 1, sz(a)){
ret = mul(ret, bexp(sz(a)-i, a[i]-a[i-1]-1));
// resto 1 pq no cuento a a[i] ya que este tiene un lugar unico
// al que ir.
}
if(allG) ret = mul(ret, n);
return ret;
}
컴파일 시 표준 에러 (stderr) 메시지
gondola.cpp: In function 'void NACHO(std::string)':
gondola.cpp:70:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)', declared with attribute warn_unused_result [-Wunused-result]
70 | freopen((name+".in").c_str(), "r", stdin);
| ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
gondola.cpp:71:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)', declared with attribute warn_unused_result [-Wunused-result]
71 | freopen((name+".out").c_str(), "w", stdout);
| ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
gondola.cpp: In function 'int replacement(int, int*, int*)':
gondola.cpp:116:37: warning: 'pos' may be used uninitialized in this function [-Wmaybe-uninitialized]
116 | rotate(id.begin(), id.begin()+a[pos]-1, id.end());
| ^
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