이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#pragma GCC optimize("O3,unroll-loops")
#include <bits/stdc++.h>
#pragma pack(0)
#define int long long
#define ll long long
#define pii pair<ll, ll>
#define pll pair<ll, ll>
#define F first
#define S second
#define MOD 1000000007
#define MOD2 998244353
#define _INFINITY 9223372036854775807
#define fast ios::sync_with_stdio(0), cin.tie(0)
using namespace std;
ll n, k, ans1, ans2 = 1e18;
vector<int> v;
vector<pii> u;
signed main()
{
fast;
cin >> k >> n;
for (int i = 1; i <= n; i++)
{
char c1, c2;
int p1, p2;
cin >> c1 >> p1 >> c2 >> p2;
if (c1 == c2)
ans1 += 2 * abs(p1 - p2);
else
{
v.emplace_back(p1);
v.emplace_back(p2);
u.emplace_back(make_pair(p1, p2));
}
}
sort(v.begin(), v.end());
if (k == 1)
{
ans2 = 0;
if (v.size() % 2)
{
int mid = 2 * v[v.size() / 2];
for (int i : v)
ans2 += abs(mid - i * 2) + 1;
}
else if (v.size() > 0)
{
int mid = v[v.size() / 2] + v[v.size() / 2 - 1];
for (int i : v)
ans2 += abs(mid - i * 2) + 1;
}
cout << (ans2 + ans1) / 2 << '\n';
}
else
{
for (int i : v)
for (int j : v)
{
ll res = 0;
for (pii p : u)
res += min(abs(p.F - i) + abs(p.S - i) + 1, abs(p.F - j) + abs(p.S - j) + 1);
ans2 = min(ans2, res);
}
cout << ans1 / 2 + ans2 << '\n';
}
}
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