제출 #379405

#제출 시각아이디문제언어결과실행 시간메모리
379405rk42745417Birthday gift (IZhO18_treearray)C++17
0 / 100
20 ms24044 KiB
/* -------------- | / | | / | | / | * |/ | | ------ * | | | | / \ | | |\ | | | |\ | \ | | | \ | | | | \ | \ | | | \ | | \ / \ | V | | \ \__/| ----- \ | */ #include <bits/stdc++.h> using namespace std; #define EmiliaMyWife ios::sync_with_stdio(0); cin.tie(NULL); using ll = int64_t; using ull = uint64_t; using ld = long double; using uint = uint32_t; const double EPS = 1e-8; const int INF = 0x3F3F3F3F; const ll LINF = 4611686018427387903; const int MOD = 1e9+7; /*--------------------------------------------------------------------------------------*/ const int N = 2e5 + 25, LGN = 19; vector<int> edge[N]; int anc[LGN][N], dep[N]; void dfs(int u, int p) { for(int v : edge[u]) if(v != p) dep[v] = dep[u] + 1, anc[0][v] = u, dfs(v, u); } int lca(int a, int b) { if(dep[a] < dep[b]) swap(a, b); for(int i = 0, x = dep[a] - dep[b]; i < LGN; i++) if(x >> i & 1) a = anc[i][a]; if(a == b) return a; for(int i = LGN - 1; ~i; i--) { if(anc[i][a] != anc[i][b]) { a = anc[i][a]; b = anc[i][b]; } } return anc[0][a]; } set<int> one[N], two[N]; signed main() { EmiliaMyWife int n, m, q; cin >> n >> m >> q; for(int i = 1, a, b; i < n; i++) { cin >> a >> b; edge[a].push_back(b); edge[b].push_back(a); } dfs(1, 1); for(int i = 1; i < LGN; i++) for(int j = 1; j <= n; j++) anc[i][j] = anc[i - 1][anc[i - 1][j]]; vector<int> arr(m + 1); for(int i = 1; i <= m; i++) cin >> arr[i], one[arr[i]].insert(i); for(int i = 2; i <= n; i++) two[lca(arr[i - 1], arr[i])].insert(i - 1); while(q--) { int t; cin >> t; if(t == 1) { int p, v; cin >> p >> v; one[arr[p]].erase(p); if(p > 1) two[lca(arr[p - 1], arr[p])].erase(p - 1); if(p + 1 <= m) two[lca(arr[p], arr[p + 1])].erase(p); arr[p] = v; one[arr[p]].insert(p); if(p > 1) two[lca(arr[p - 1], arr[p])].insert(p - 1); if(p + 1 <= m) two[lca(arr[p], arr[p + 1])].insert(p); } else { int l, r, v; cin >> l >> r >> v; auto it = one[v].lower_bound(l); auto it2 = two[v].lower_bound(l); if(it != one[v].end() && *it <= r) cout << *it << ' ' << *it << '\n'; else if(it2 != two[v].end() && *it2 < r) cout << *it2 << ' ' << *it2 + 1 << '\n'; else cout << "-1 -1\n"; } } } /* 5 4 4 1 2 3 1 3 4 5 3 4 5 2 3 2 1 3 1 1 3 5 2 3 4 5 2 1 3 1 */
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