This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
#define ii pair<int, int>
#define f first
#define s second
#define pb push_back
#define mp make_pair
#define all(x) x.begin(), x.end()
#define sz(x) (int)x.size()
#define F0R(i, n) for (int i = 0; i < n; i++)
#define FOR(i, a, b) for (int i = a; i < b; i++)
#define inf 1000000010
#define maxn 500010
int ans[maxn];
int maxPrefix[4*maxn], sum[4*maxn];
// first is sum, second is max prefix
ii qry(int p, int i, int j, int L, int R) {
if (i > R || j < L) return mp(0, -inf);
if (L <= i && j <= R) {
return mp(sum[p], maxPrefix[p]);
}
ii lft = qry(p*2, i, (i+j)/2, L, R);
ii rht = qry(p*2+1, (i+j)/2+1, j, L, R);
return mp(lft.f + rht.f, max(lft.s, lft.f + rht.s));
}
void upd(int p, int i, int j, int k, int v) {
if (i > k || j < k) return;
if (i == j && j == k) {
maxPrefix[p] = v;
sum[p] = v;
return;
}
upd(p*2, i, (i+j)/2, k, v);
upd(p*2+1, (i+j)/2+1, j, k, v);
maxPrefix[p] = max(maxPrefix[p*2], sum[p*2]+maxPrefix[p*2+1]);
sum[p] = sum[p*2]+sum[p*2+1];
}
int bit[maxn];
int get(int k) {
int s = 0;
while (k) {
s += bit[k];
k -= k&-k;
}
return s;
}
void add(int k, int v) {
while (k < maxn) {
bit[k] += v;
k += k&-k;
}
}
int main() {
cin.tie(0)->sync_with_stdio(0);
int n; cin >> n;
string s; cin >> s; s = " " + s;
int q; cin >> q;
vector<pair<ii, int>> queries;
F0R(i, q) {
int l, r; cin >> l >> r;
queries.pb(mp(mp(l, r), i));
}
sort(all(queries), [](pair<ii, int> a, pair<ii, int> b) { return a.f.s < b.f.s; });
int idx = 0;
stack<int> removedT;
for (int i = 1; i <= n; i++) {
if (s[i] == 'C') {
upd(1, 1, n, i, -1);
if (!removedT.empty()) {
int tgt = removedT.top();
add(tgt, -1);
upd(1, 1, n, tgt, 1);
removedT.pop();
}
} else {
removedT.push(i);
add(i, 1);
}
while (idx < q && queries[idx].f.s == i) {
// process query idx
int toRemove = get(queries[idx].f.s) - get(queries[idx].f.f-1);
int extraRemove = qry(1, 1, n, queries[idx].f.f, queries[idx].f.s).s;
ans[queries[idx].s] = toRemove + max(extraRemove, 0);
idx++;
}
}
F0R(i, q) cout << ans[i] << endl;
return 0;
}
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