제출 #37895

#제출 시각아이디문제언어결과실행 시간메모리
37895MatheusLealV수열 (APIO14_sequence)C++14
71 / 100
2000 ms90660 KiB
#include <bits/stdc++.h> #define N 100005 #define K 202 #define inf 200000000000000000LL #define f first #define s second using namespace std; typedef long long ll; typedef pair<ll, ll> pii; int n, k, r, block[N], qtd, prox[N][K]; ll dp[N][3], sum[N]; void fastscan(int &number) { register int c; number = 0; c = getchar(); for (; (c>47 && c<58); c=getchar()) number = number *10 + c - 48; } void fast_ll(ll &number) { register int c; number = 0; c = getchar(); for (; (c>47 && c<58); c=getchar()) number = number *10 + c - 48; } inline bool bad(pii A, pii B, pii C) { pii r, s; r = A, s = C; double a = ((double)(r.s - s.s))/((double)(s.f - r.f)); r = B, s = A; double b = ((double)(r.s - s.s))/((double)(s.f - r.f)); return a >= b; } inline void addline(vector< pair<pii, int> > &line, pair<pii, int> l) { if(line.size() && line.back().f.f == l.f.f) { if(line.back().f.s < l.f.s) return; if(line.back().f.s == l.f.s && line.back().s < l.s) return; line.pop_back(); line.push_back(l); return; } while(line.size() >= 2 && bad( line[line.size() - 2].f, line.back().f, l.f )) line.pop_back(); line.push_back(l); } inline pair<ll, int> query(vector< pair<pii, int> > &line, int x) { int p = line.size(); if(r >= p) r = p - 1; while(r < p - 1 && line[r].f.f*x + line[r].f.s > line[r + 1].f.f*x + line[r + 1].f.s)r++; return pii(line[r].f.f*x + line[r].f.s, line[r].s); } int32_t main() { //ios::sync_with_stdio(false); cin.tie(0); fastscan(n), fastscan(k); for(int i = 1; i <= n; i++) fast_ll(sum[i]), sum[i] += sum[i - 1]; for(int i = 0; i <= n; i++) dp[i][0] = 0; for(int i = 0; i <= k; i++) dp[n][i] = 0; int A = 1, B = 0; for(int q = 1; q <= k ; q++) { vector< pair<pii, int> > line; for(int i = n - 1; i >= 1; i--) { addline(line, make_pair(pii( -sum[i], -(sum[i]*sum[n] - sum[i]*sum[i] + dp[i + 1][ B ] )), i)); pair<ll, int> best = query(line, sum[i - 1]); dp[i][A] = -best.f - sum[i - 1]*sum[n]; prox[i][q] = best.s; } swap(A, B); } printf("%lld\n", dp[1][k%2]); int ini = 1, q = k; while(true) { if(!prox[ini][q]) break; qtd ++; block[prox[ini][q]] = 1; printf("%d ", prox[ini][q]); ini = prox[ini][q] + 1; q --; } int extra = k - qtd; for(int i = 1, cnt = 0; i <= n && cnt < extra; i++) { if(!block[i]) printf("%d ", i), cnt ++; } cout<<"\n"; }
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