제출 #378273

#제출 시각아이디문제언어결과실행 시간메모리
378273AmineWeslati휴가 (IOI14_holiday)C++14
47 / 100
495 ms2028 KiB
//Never stop trying #include "bits/stdc++.h" using namespace std; #define boost ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0) typedef long long ll; typedef string str; typedef long double ld; typedef pair<int, int> pi; #define fi first #define se second typedef vector<int> vi; typedef vector<pi> vpi; #define pb push_back #define eb emplace_back #define sz(x) (int)x.size() #define all(x) begin(x), end(x) #define rall(x) rbegin(x), rend(x) #define endl "\n" #define FOR(i,a,b) for (int i = (a); i < (b); ++i) #define ROF(i,a,b) for (int i = (b)-1; i >= (a); --i) const int MOD = 1e9 + 7; //998244353 const ll INF = 1e18; const int MX = 2e5 + 10; const int nx[4] = {0, 0, 1, -1}, ny[4] = {1, -1, 0, 0}; //right left down up template<class T> using V = vector<T>; template<class T> bool ckmin(T& a, const T& b) { return a > b ? a = b, 1 : 0; } template<class T> bool ckmax(T& a, const T& b) { return a < b ? a = b, 1 : 0; } ll cdiv(ll a, ll b) { return a / b + ((a ^ b) > 0 && a % b); } // divide a by b rounded up //constexpr int log2(int x) { return 31 - __builtin_clz(x); } // floor(log2(x)) mt19937 rng(chrono::system_clock::now().time_since_epoch().count()); //mt19937_64 rng(chrono::system_clock::now().time_since_epoch().count()); ll random(ll a, ll b){ return a + rng() % (b - a + 1); } #ifndef LOCAL #define cerr if(false) cerr #endif #define dbg(x) cerr << #x << " : " << x << endl; #define dbgs(x,y) cerr << #x << " : " << x << " / " << #y << " : " << y << endl; #define dbgv(v) cerr << #v << " : " << "[ "; for(auto it : v) cerr << it << ' '; cerr << ']' << endl; #define here() cerr << "here" << endl; void IO() { #ifdef LOCAL freopen("input.txt", "r", stdin); freopen("output.txt", "w", stdout); #endif } /////////////////////////ONLY CLEAN CODES ALLOWED///////////////////////// #ifndef LOCAL #include"holiday.h" #endif int N,st,D; vi a; int f(int l, int m, int r){ return r-l+min(m-l,r-m); } ll findMaxAttraction(int N, int st, int D, int tab[]) { ::N=N; ::st=st; ::D=D; a.resize(N); FOR(i,0,N) a[i]=tab[i]; if(N<=3000){ ll ans=0; FOR(i,st,N){ int r=D-f(st,st,i); if(r<0) break; ll sum=0; multiset<int>s; FOR(j,st+1,i+1) s.insert(a[j]),sum+=a[j]; ROF(j,0,st+1){ s.insert(a[j]); sum+=a[j]; r=D-f(j,st,i); if(r<0) break; while(sz(s)>r){ sum-=*s.begin(); s.erase(s.begin()); } ckmax(ans,sum); } } return ans; } else{ vi cnt(101,0); ll ans=0; FOR(i,0,N){ cnt[a[i]]++; int r=D-i; if(r<0) break; ll cur=0; ROF(j,0,101){ int n=min(cnt[j],r); r-=n; cur+=j*n; } ckmax(ans,cur); } return ans; } return 0; } #ifdef LOCAL int main() { boost; IO(); int N,st,D; cin>>N>>st>>D; int a[N]; FOR(i,0,N) cin>>a[i]; cout << findMaxAttraction(N,st,D,a) << endl; return 0; } #endif //Change your approach
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