제출 #378066

#제출 시각아이디문제언어결과실행 시간메모리
378066nextgenxingBosses (BOI16_bosses)C++14
0 / 100
1 ms492 KiB
#include <bits/stdc++.h> using namespace std; typedef long long ll; typedef pair<int, int> pii; typedef pair<ll, ll> pll; #define f first #define s second #define all(x) begin(x), end(x) #define rall(x) (x).rbegin(), (x).rend() #define sz(x) (int)(x).size() #define FOR(i, a, b) for(int i = (a); i < (b); i++) #define F0R(i, x) FOR(i, 0, x) #define FORd(i, a, b) for(int i = (b)-1; i >= (a); i--) #define F0Rd(i, x) FORd(i, 0, x) #define ckif(a, b, c) ((c) ? (a) : (b)) const int MAX_N = 5001; const ll MOD = 1000000007; const ll INF = 1e18; int n; vector<int> adj[MAX_N]; int main(int argc, const char * argv[]){ ios_base::sync_with_stdio(0), cin.tie(0); cin >> n; F0R(i, n){ int a; cin >> a; F0R(j, a){ int x; cin >> x; x--; adj[x].push_back(a); } } ll ans = INF; F0R(i, n){ // i is the root of the tree // ans for this root is just the sum of the depths of all nodes // it is optimal to use the shortest path tree starting from i vector<ll> dist(n, -1); queue<pll> q; q.push({i, 1}); while(!q.empty()){ ll curr = q.front().f, cost = q.front().s; q.pop(); if(~dist[curr]) continue; dist[curr] = cost; for(int child : adj[curr]) q.push({child, cost+1}); } ll tot = 0, mn = 0; F0R(j, n) tot += dist[j], mn = min(mn, tot); if(~mn) ans = min(ans, tot); } cout << ans << endl; return 0; }
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