이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
#define ii pair<int, int>
#define f first
#define s second
#define pb push_back
#define mp make_pair
#define all(x) x.begin(), x.end()
#define sz(x) (int)x.size()
#define F0R(i, n) for (int i = 0; i < n; i++)
#define FOR(i, a, b) for (int i = a; i < b; i++)
#define inf 1000000010
ll solve(vector<int> need, int depth) {
if (depth > 12) return -1;
if (need.size() == 1) {
ll ans = 0;
bool needzero = false;
F0R(i, 10) {
int j = i;
if (need[0] & (1 << j)) {
if (j == 0) {
needzero = 1;
} else {
ans = ans*10+j;
if (needzero) {
ans = ans*10;
needzero = 0;
}
}
}
}
if (ans == 0 && needzero) return 10;
return ans;
}
ll ans = -1;
F0R(lastDigit, 10) {
vector<int> next;
int curDigit = lastDigit;
int curMask = 0;
for (auto x : need) {
curMask |= x & ~(1 << curDigit);
curDigit++;
if (curDigit == 10) {
next.pb(curMask);
curDigit = 0;
curMask = 0;
}
}
if (curDigit != 0) next.pb(curMask);
ll ans2 = solve(next, depth + 1);
if (ans2 == -1) continue;
ll nxt = ans2*10+lastDigit;
if (lastDigit == 0 && ans2 == 0 && need[0] != 0) nxt = 10;
if (ans == -1 || nxt < ans) {
ans = nxt;
}
}
return ans;
}
int main() {
cin.tie(0)->sync_with_stdio(0);
int k; cin >> k;
vector<int> A;
F0R(i, k) {
int x; cin >> x;
A.pb(1 << x);
}
cout << solve(A, 1) << endl;
return 0;
}
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