제출 #375828

#제출 시각아이디문제언어결과실행 시간메모리
375828fhvirusTwo Dishes (JOI19_dishes)C++17
0 / 100
206 ms9836 KiB
// Knapsack DP is harder than FFT. #include<bits/stdc++.h> using namespace std; typedef long long ll; typedef pair<int, int> pii; typedef pair<ll, ll> pll; #define ff first #define ss second #define pb emplace_back #define FOR(i,n) for(int i = 0; i < (n); ++i) #define FOO(i,a,b) for(int i = (a); i <= (b); ++i) #define AI(x) begin(x),end(x) template<typename I> bool chmax(I &a, I b){ return a < b ? ( a = b, true ) : false;} template<typename I> bool chmin(I &a, I b){ return a > b ? ( a = b, true ) : false;} #ifdef OWO #define debug(args...) LKJ("[ " + string(#args) + " ]", args) void LKJ(){cerr<<endl;} template<class I, class...T> void LKJ(I&&x, T&&...t){ cerr<<x<<", ", LKJ(t...);} template<class I> void DE(I a, I b){ while(a < b) cerr<<*a<<" \n"[next(a) == b], ++a;} #else #define debug(...) 0 #define DE(...) 0 #endif const int N = 1e6 + 225; int n, m; ll a[N], b[N], s[N], t[N], p[N], q[N]; ll dp[N]; int bs(int lft){ int l = 0, r = m, mid; while(l < r){ mid = (l + r) / 2; if(b[mid] <= lft) l = mid + 1; else r = mid; } return l - 1; } void solve1(){ FOO(i,1,n) a[i] += a[i-1]; FOO(i,1,m) b[i] += b[i-1]; int ans = 0; FOO(i,1,n){ if(a[i] > s[1]) break; int left = s[1] - a[i]; chmax(ans, i + bs(left)); } cout << ans; } int32_t main(){ ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0); cin >> n >> m; FOO(i,1,n) cin >> a[i] >> s[i] >> p[i]; FOO(i,1,m) cin >> b[i] >> t[i] >> q[i]; solve1(); return 0; }
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