제출 #374746

#제출 시각아이디문제언어결과실행 시간메모리
374746jainbot27Bulldozer (JOI17_bulldozer)C++17
0 / 100
3 ms640 KiB
#include <bits/stdc++.h> using namespace std; #define f first #define s second #define pb push_back #define ar array #define all(x) x.begin(), x.end() #define siz(x) (int)x.size() #define FOR(x, y, z) for(int x = (y); x < (z); x++) #define ROF(x, z, y) for(int x = (y-1); x >= (z); x--) #define F0R(x, z) FOR(x, 0, z) #define R0F(x, z) ROF(x, 0, z) #define trav(x, y) for(auto&x:y) using ll = long long; using vi = vector<int>; using vl = vector<long long>; using pii = pair<int, int>; using pll = pair<ll, ll>; using vpii = vector<pair<int, int>>; template<class T> inline bool ckmin(T&a, T b) {return b < a ? a = b, 1 : 0;} template<class T> inline bool ckmax(T&a, T b) {return b > a ? a = b, 1 : 0;} mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); const char nl = '\n'; const int mxN = 2001; const int MOD = 1e9 + 7; const long long infLL = 1e18; struct Frac{ long long n, d; Frac(long long n, long long d){ if(d == 0){ this->d = 0; this->n = 1; return; } this->n = n; this->d = d; long long g = __gcd(n, d); this->n/=g; this->d/=g; if(this->d < 0){ this->n*=-1; this->d*=-1; }; } Frac(long long n){ this->n = n; d = 1; } Frac(){n = 0; d = 1;} Frac operator-(){return Frac(-n, d);} Frac operator+=(const Frac& other){return Frac(n*other.d + other.n*d, d*other.d);} Frac operator-=(const Frac& other){return Frac(n*other.d - other.n*d, d*other.d);} Frac operator*=(const Frac& other){return Frac(n*other.n, d*other.d);} Frac operator/=(const Frac& other){return Frac(n*other.d, d*other.n);} friend Frac operator+(Frac a, const Frac& b){ return a+=b; } friend Frac operator-(Frac a, const Frac& b){ return a-=b; } friend Frac operator*(Frac a, const Frac& b){ return a*=b; } friend Frac operator/(Frac a, const Frac& b){ return a/=b; } bool operator==(const Frac& other){ return n==other.n && d==other.d; } bool operator<(const Frac& other){ return n*other.d < other.n*d; } bool operator!=(const Frac& other){ return !((*this)==other);} friend string ts(const Frac& a){ return to_string(a.n) + "/" + to_string(a.d); } friend ostream& operator<<(ostream& out, Frac &a) { return out << ts(a); } }; typedef ar<ll, 4> T; T unit = {0, 0, 0, 0}; struct Tree { //[maxpref, maxsuf, maxsum, sum] T f(T a, T b) { T res; res[0] = max({a[0], a[3]+b[0], 0LL}); res[1] = max({b[1], a[1]+b[3], 0LL}); res[2] = max({a[2], b[2], a[1]+b[0], 0LL}); res[3] = a[3]+b[3]; //cout << "a: " << a[0] << ' ' << a[1] << ' ' << a[2] << ' ' << a[3] << nl; //cout << "b: " << b[0] << ' ' << b[1] << ' ' << b[2] << ' ' << b[3] << nl; //cout << "res: " << res[0] << ' ' << res[1] << ' ' << res[2] << ' ' << res[3] << nl; return res; } // (any associative fn) vector<T> s; int n; Tree(int n = 0, T def = unit) : s(2*n, def), n(n) {} void update(int pos, T val) { for (s[pos += n] = f(val, unit); pos /= 2;) s[pos] = f(s[pos * 2], s[pos * 2 + 1]); } T query(int b, int e) { // query [b, e) T ra = unit, rb = unit; for (b += n, e += n; b < e; b /= 2, e /= 2) { if (b % 2) ra = f(ra, s[b++]); if (e % 2) rb = f(s[--e], rb); } return f(ra, rb); } }; int n; pair<pll, ll> a[mxN]; vector<pair<Frac, pii>> v; int pos[mxN]; ll ans = 0; int32_t main(){ ios_base::sync_with_stdio(0); cin.tie(0); cin >> n; F0R(i, n) cin >> a[i].f.f >> a[i].f.s >> a[i].s; sort(a, a+n); F0R(i, n){ F0R(j, i){ v.pb({Frac(a[i].f.s-a[j].f.s, a[i].f.f-a[j].f.f), {j, i}}); } } sort(all(v), [](pair<Frac, pii> A, pair<Frac, pii> B){ if(A.f==B.f) return A.s < B.s; return A.f < B.f; }); F0R(i, n) pos[i] = i; Tree st(n); F0R(i, n){ ll val = a[i].s; st.update(i, {val, val, val, val}); } //cout << st.query(0, n)[2] << nl; //exit(0); F0R(i, siz(v)){ swap(pos[v[i].s.f], pos[v[i].s.s]); ll val = a[v[i].s.f].s; st.update(pos[v[i].s.f], {val, val, val, val}); val = a[v[i].s.s].s; st.update(pos[v[i].s.s], {val, val, val, val}); if(i==siz(v)-1||v[i].f!=v[i+1].f){ ckmax(ans, st.query(0, n)[2]); } } cout << ans << nl; return 0; }
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